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ad-work [718]
3 years ago
12

Choose the graph which represents the solution to the inequality: 1 2 x + 8 ≤ 3 A) B) C) D)

Mathematics
1 answer:
ankoles [38]3 years ago
5 0
The answer is choice B
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Please help ! Easy 7th grade work .
Tpy6a [65]

Answer:

1-9 answers

Step-by-step explanation:

1=-38

2=-25

3=16

4=-4

5=0

6=-34

7=9

8=-7

9=-4

5 0
3 years ago
Read 2 more answers
Royal lawncare company produces and sells two packaged products
MrRa [10]
Royal Lawncare Company produces and sells two packaged products. Weedban and Greengrow. Revenue and cost information relating to the products follow: Product Weedban Greengrow Selling price per unit $ 11.00 $ 36.00 Variable expenses per unit $ 3.00 $ 14.00 Traceable fixed expenses per year $ 136.000 $ 31.000 Common fixed expenses in the company total $96.000 annually. Last year the company produced and sold 37.000 units of Weedban and 15.500 units of Greengrow. Required: Prepare a contribution format income statement segmented by product lines. Product Line Total Company Weedban Greengrow Sales Variable expenses Contribution margin Traceable fixed expenses Product line segment margin Common fixed expenses not traceable to products Net operating income
7 0
3 years ago
Blue Ribbon taxis offers shuttle service to the nearest airport. You look up the online reviews for Blue Ribbon taxis and find t
Anon25 [30]

Answer:

(d) there is not enough information to tell if this is a biased sampling method.

Step-by-step explanation:

Based on reviews we cannot conclude whether the sampling is biased or not, if only we can know the total number of times the taxi was ordered then we can conclude.

3 0
3 years ago
Help please help!! my grade is down​
lisov135 [29]

plug in -2 for x

7*-2 -10 = -24

7 0
3 years ago
Given: KLMN is a trapezoid m∠N = m∠KML ME ⊥ KN , ME = 3 5 , KE = 8, LM KN = 3 5 Find: KM, LM, KN, Area of KLMN
prisoha [69]
A) Find KM∠KEM is a right angle hence ΔKEM is a right angled triangle Using Pythogoras' theorem where the square of hypotenuse is equal to the sum of the squares of the adjacent sides we can answer the 
KM² = KE² + ME²KM² = 8² + (3√5)²       = 64 + 9x5KM = √109KM = 10.44
b)Find LMThe ratio of LM:KN is 3:5 hence if we take the length of one unit as xlength of LM is 3xand the length of KN is 5x ∠K and ∠N are equal making it a isosceles trapezoid. A line from L that cuts KN perpendicularly at D makes KE = DN
KN = LM + 2x 2x = KE + DN2x = 8+8x = 8LM = 3x = 3*8 = 24
c)Find KN Since ∠K and ∠N are equal, when we take the 2 triangles KEM and LDN, they both have the same height ME = LD.
∠K = ∠N  Hence KE = DN the distance ED = LMhence KN = KE + ED + DN since ED = LM = 24and KE + DN = 16KN = 16 + 24 = 40
d)Find area KLMNArea of trapezium can be calculated using the  formula below Area = 1/2 x perpendicular height between parallel lines x (sum of the parallel sides)substituting values into the general equationArea = 1/2 * ME * (KN+ LM)          = 1/2 * 3√5 * (40 + 24)         = 1/2 * 3√5 * 64         = 3 x 2.23 * 32         = 214.66 units²
7 0
3 years ago
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