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Alex777 [14]
3 years ago
11

What is the solution to the inequality below?

Mathematics
1 answer:
Marta_Voda [28]3 years ago
4 0
24...................................................................
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How do I solve this absolute value in quality problem <br><br> |2t + 2/3|≤4
xenn [34]

Answer: -7/3≤t≤5/3

Step-by-step explanation:

|2t + 2/3|≤4

2t + 2/3≤4

(2t + 2/3≤4)*3

6t+2≤12

6t≤10

t≤10/6

<u>t≤5/3</u>

2t + 2/3>=-4

(2t + 2/3>=-4)*3

6t + 2>=-12

6t>=-14

t>=-14/6

<u>t>=-7/3</u>

-7/3≤t≤5/3

6 0
2 years ago
What's -8+9w+(-23) <br> ????
zvonat [6]
First simplify
-8+9w-23
Then Group simliar terms
(-8-23)+9w
After simplify
-31 +9w
8 0
3 years ago
How do you solve the problem 2p = 60 ​
d1i1m1o1n [39]
You have to separate the 2 and p so divide 60 by 2 which will leave p=30 and now if you plug it in you see 2 times 30 equals 60 :)
4 0
3 years ago
Please help asap :DDD
Musya8 [376]
X< 5 and (- infinity, 5 )
4 0
2 years ago
Read 2 more answers
If the length of the square is increased by 2 and the width is decreased by 2, by how many units is the area of
mrs_skeptik [129]

Answer:

4 units

Step-by-step explanation:

Let x represent the length of the square

Area of the square = x^2

So, the dimension of the rectangle formed is:

length = x + 2

width = x - 2

Area of the rectangle = ( x + 2 ) * ( x - 2 )

solve the parenthesis

x^2 - 2x + 2x - 4

Area of the rectangle = x^2 - 4

subtract this area from that of the square

x^2 - ( x^2 - 4 )

=x^2 - x^2 + 4

= 4 units

3 0
4 years ago
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