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3 years ago

11

What is the solution to the inequality below?

1 answer:

Marta_Voda [28]3 years ago

4 0

24...................................................................

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1. How many ways can eight different types of soaps be displayed on a shelf in a grocery store?

castortr0y [4]

Answer:

8^8 = 16777216

Step-by-step explanation:

3 0

3 years ago

Expanding log functions<br> ㏒3 (3(x+1)(x+2))

Oksanka [162]

Log(ab)=log(a)+log(b)
log_a(a)=1
so

$log_3(3(x+1)(x+2))=log_3(3)+log_3(x+1)+log(x+2)=$ $1+log_3(x+1)+log_3(x+2)$

6 0

3 years ago

What are the rational numbers of -12,0,35,4.85,√12,√36,19/6,-10/11,1.4949949994

klemol [59]

All of those numbers are rational, except the square root of 12.

6 0

3 years ago

Find the area of the shaded region. Round the nearest hundredth if necessary. YZ=14.2m

andreyandreev [35.5K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

1

$A_1 = 67.58 \ in^2$

2

$A_2 =415.4 \ ft^2$

3

$A_3 = 8.48 \ cm^2$

4

$A_4 = 480.38 \ m^2$

Step-by-step explanation:

Generally the area of a sector is mathematically represented as

$A = \frac{\theta}{360} * \pi r^2$

Now at $r_1 = 11 in$ and $\theta_1 = 64^o$

$A_1 = \frac{64}{360} * 3.142 * 11^2$

$A_1 = 67.58 \ in^2$

Now at $r_2 = 20 ft$ in and $\theta_2 = 119 ^o$

$A_2 = \frac{119}{360} * 3.142 * 20^2$

$A_2 =415.4 \ ft^2$

Now at $r_3 = 6.5 cm$ and $\theta_3 = 23 ^o$

$A_3 = \frac{23}{360} * 3.142 * 6.5 ^2$

$A_3 = 8.48 \ cm^2$

Now at $r_4 = 14.2 m$ and $\theta_4 = 360 -87 = 273 ^o$

$A_4 = \frac{273}{360} * 3.142 * 14.2^2$

$A_4 = 480.38 \ m^2$

6 0

3 years ago

Which of the following sets represents MUN?

Anuta_ua [19.1K]

Answer:

<u>Third choice: {3, 4, 6, 7, 9}</u>

Explanation:

<em>M ∪ N</em> means the union of the segments M and N. That is, the complete list of objects that are either in the set M or N.

The circle on the left of diagram shows that the elements inside the set M are 3, 4, 7 and 9.

The circle on the right of the diagram shows that the elements inside the set N are 4, 6 and 7.

The complete list of the numbers in either M or N is 3, 4, 6, 7, and 9 (you must not repeat the elements that belong to both sets but indicate them just once.

So, the set that represents M ∪ N is the third option {3, 4, 6, 7, 9}.

7 0

3 years ago