We know that
<span>the regular hexagon can be divided into 6 equilateral triangles
</span>
area of one equilateral triangle=s²*√3/4
for s=3 in
area of one equilateral triangle=9*√3/4 in²
area of a circle=pi*r²
in this problem the radius is equal to the side of a regular hexagon
r=3 in
area of the circle=pi*3²-----> 9*pi in²
we divide that area into 6 equal parts------> 9*pi/6----> 3*pi/2 in²
the area of a segment formed by a side of the hexagon and the circle is equal to <span>1/6 of the area of the circle minus the area of 1 equilateral triangle
</span>so
[ (3/2)*pi in²-(9/4)*√3 in²]
the answer is
[ (3/2)*pi in²-(9/4)*√3 in²]
The answer is 5 . because if you count the # it will go to 28
Answer:
Step-by-step explanation:
1 + 3 = 4
so find the point 1/4 of the way from (-1, 2) to (7, 8)
x coordinate
Δx = ¼(7 - (-1)) = 2
x = x₀ + Δx
x = -1 + 2 = 1
y coordinate
Δy = ¼(8 - 2) = 1½
y = y₀ + Δy
y = 2 + 1½ = 3½
(1, 3½)
The answer is nonlinear. It goes in a sharp downward curve, whereas a linear function is a straight line.
