Since we are given with the identity of the chemical as Carbon-14, we obtain the half-life of the chemical from a reliable source and get a value of 5730 years. The equation that we are going to use for this item is,
A(t)/A(0) = (0.50)^(n/5730)
where A(t) is the current amount, A(0) is the initial amount and n is the number of years. We know from the given that the ratio of A(t) and A(0) is equal to 0.63. Substituting this to the given,
0.63 = 0.50^(n/5730)
n = 3819.48
Thus, the sample is approximately 3819.5 years old.
I think it would be the first one? 2 units to the left of g(x).
Answer: 
Explanation:
The equation is:
The term on the left consists of a product of two different factors: therefore, this product can be zero if either the first term (2x-5) or the second term (3x-1) is equal to zero.
This means that we can solve separately for the two terms:
Solving the first equation:
Solving the second equation:
Answer: x = -7/3
Step-by-step explanation:
https://www.symbolab.com/solver/step-by-step/%5Cleft(3x%20%2B%207%5Cright)2%20%3D%20-6x%20-%2014
there are the steps
Answer:34
Step-by-step explanation:
First you multiply
-7•-3=21
Then you just add 9+4+21
9+4=13
21+13=34
