Let L be the low copper alloy and H be the high copper alloy.
We need 0.15L + 0.60H = 0.42 and L + H = 100
L=100 - H
Substituting this into the second equation for L, we get:
0.15(100-H) + 0.60H = 0.42(H+L)
15 - 0.15H + 0.60H = 0.42(H+100-H)
15 + 0.45H = 0.42(100)
0.45H = 42 - 15 = 27
H = 27/.45 = 60 lbs
Back substitution, L = 40 lbs.
Answer:
3.4
Step-by-step explanation:
The transformations which have made to produce the function
y₂ = 1+csc (x-π) from the <span>parent function y = csc x
</span>1. shift up one unit ⇒ shift one unit in the direction of positive y
2. shift to the left equal to π ⇒ shift π units in the direction of positive x
See the attached figure.
Blue graph represents the parent function
Red graph represents the produced function after transformation.
Answer:
7 divided by 2
Step-by-step explanation:
I say 7 divided by 2 because if you round 6 3/4 up one you will get 7 and if you round 1 2/3 up one you get 2 so 7 divided by 2 makes most sense