-4(2y)+11y=15, -8y+11y=3y=15: y=5
X=2(5)=10
To check your work -4(10)+11(5)=15
15=15
Since addition is commutative, she can add anyway she wants.
(17+51)+(10+13)
(51+10)+(17+13)
Hope this helps.
Divide by 3 on both sides:
Square root both sides:
Take away 3 from both sides:
Divide by 2 on both sides:
Answer:
Answer:
You on? I’m bored! You- you on? I’m bored
Step-by-step explanation:
For simple integer factors as this one has, you want to find two values for the quadratic in the form ax^2+bx+c. Let the two values be j and k. These two values must satisfy two conditions.
jk=ac=10 and j+k=b=11, so j and k must be 1 and 10.
Now replace bx with jx and kx...
2x^2+x+10x+5 now factor 1st and 2nd pair of terms.
x(2x+1)+5(2x+1)
(x+5)(2x+1)
