Answer:
66.0 mL HClO3
Explanation:
M1V1 = M2V2
M1 = 0.100 M HClO3
V1 = ?
M2 = 0.165 M KOH
V2 = 40.0 mL KOH
Solve for V1 --> V1 = M2V2/M1
V1 = (0.165 M)(40.0 mL) / (0.100 M) = 66.0 mL HClO3
Answer:
Percent yield = 57.8 %
Theoretical yield = 11.781 g
Explanation:
Given data:
Mass of CaO produced = 6.81 g
Mass of CaCO₃ react = 20.7 g
Theoretical yield = ?
Percent yield = ?
Solution:
Chemical equation:
CaCO₃ → CaO + CO₂
Number of moles of CaCO₃ :
Number of moles = mass/molar mass
Number of moles = 20.7 g/ 100.1 g/mol
Number of moles = 0.21 mol
Now we will compare the moles of CaCO₃ with CaO.
CaCO₃ : CaO
1 : 1
0.21 : 0.21
Theoretical yield of CaO:
Mass = number of moles × molar mass
Mass = 0.21 mol × 56.1 g/mol
Mass = 11.781 g
Percent yield:
Percent yield = ( actual yield / theoretical yield ) × 100
Percent yield = (6.81 g/ 11.781 g) × 100
Percent yield = 57.8 %
Answer:
decay because of the stone itself will start to crumble
Explanation:
<h2><em>Solid. Because molecules densely packed it has a high resistance to flow thereby lower kinetic energy.
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