Answer:
66.0 mL HClO3
Explanation:
M1V1 = M2V2
M1 = 0.100 M HClO3
V1 = ?
M2 = 0.165 M KOH
V2 = 40.0 mL KOH
Solve for V1 --> V1 = M2V2/M1
V1 = (0.165 M)(40.0 mL) / (0.100 M) = 66.0 mL HClO3
The answer is 17.03052. We assume you are converting between grams Ammonia and mole.
