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irina1246 [14]
3 years ago
12

The atomic mass of fluorine in 19.0 amu, so the molar mass is?

Chemistry
1 answer:
Burka [1]3 years ago
5 0

Answer:

the molar mass for fluorine is 37.99681 g/mol

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A dominant allele will always allow a specific trait to show up no matter if we have two dominant copies (BB) or just one (Bb). A trait from a recessive allele will only appear if it is paired with another recessive allele

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probably causes most variations in individuals ? Sunlight b . gene mutations c . poisons d. cell phones
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What is row of the periodic table called
Anvisha [2.4K]

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7 0
2 years ago
19. Which of the following chemical equations represents
Lesechka [4]

Answer:

  • C₃H₈ (g) + 5O₂(g) → 3CO₂ (g) + 4H₂O (l)

(option D. with the proviso that the subscripts of propane's chemical formula must be corrected)

Explanation:

<em>Propane</em> is the saturated hydrocarbon, alkane, with chemical formula C₃H₈ or CH₃CH₂CH₃.

The complete combustion of the hydrocarbons yield carbon dioxide (CO₂) and water (H₂O).

The chemical equation that represents this combustion is:

  • C₃H₈ (g) + O₂(g) → CO₂ (g) + H₂O (l) (skeleton equation: unbalanced)

Once you balance it, you get:

  • C₃H₈ (g) + 5O₂(g) → 3CO₂ (g) + 4H₂O (l)

        Left side           Right side

C         3                          3

H         8                          4×2 = 8

O        5×2 = 10               3×2 + 4 = 10

That equation corresponds to the option D. of the list, with the proviso that the subscripts of propane's chemical formula must be corrected

6 0
2 years ago
While ethanol (CH3CH2OH) is produced naturally by fermentation, e.g. in beer- and wine-making, industrially it is synthesized by
grin007 [14]

Answer:

n_{C2H_5OH}^{eq}=14.234mol

Explanation:

Hello,

In this case, the reaction is:

C_2H_4+H_2O\rightleftharpoons CH_3CH_2OH

Thus, the law of mass action turns out:

Kc=\frac{[CH_3CH_2OH]_{eq}}{[H_2O]_{eq}[CH_2CH_2]_{eq}}

Thus, since at the beginning there are 29 moles of ethylene and once the equilibrium is reached, there are 16 moles of ethylene, the change x result:

[CH_2CH_2]_{eq}=29mol-x=16mol\\x=29-16=13mol

In such a way, the equilibrium constant is then:

Kc=\frac{\frac{x}{V} }{\frac{16mol}{V}* \frac{3mol}{V}} =\frac{\frac{13mol}{75.0L} }{\frac{16mol}{75.0L}* \frac{3mol}{75.0L}} =20.31

Thereby, the initial moles for the second equilibrium are modified as shown on the denominator in the modified law of mass action by considering the added 15 moles of ethylene:

Kc=\frac{\frac{13+x_2}{V} }{\frac{16+15-x_2}{V}* \frac{3-x_2}{V}}  =20.31

Thus, the second change, x_2 finally result (solving by solver or quadratic equation):

x_2=1.234mol

Finally, such second change equals the moles of ethanol after equilibrium based on the stoichiometry:

n_{C2H_5OH}^{eq}=x+x_2=13mol+1.234mol\\n_{C2H_5OH}^{eq}=14.234mol

Best regards.

5 0
3 years ago
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