Answer:
A dominant allele will always allow a specific trait to show up no matter if we have two dominant copies (BB) or just one (Bb). A trait from a recessive allele will only appear if it is paired with another recessive allele
Explanation:
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Hi how are you Henson’s dndndndndndndn
Explanation:
row of the periodic table called periods
and group
Answer:
- C₃H₈ (g) + 5O₂(g) → 3CO₂ (g) + 4H₂O (l)
(option D. with the proviso that the subscripts of propane's chemical formula must be corrected)
Explanation:
<em>Propane</em> is the saturated hydrocarbon, alkane, with chemical formula C₃H₈ or CH₃CH₂CH₃.
The complete combustion of the hydrocarbons yield carbon dioxide (CO₂) and water (H₂O).
The chemical equation that represents this combustion is:
- C₃H₈ (g) + O₂(g) → CO₂ (g) + H₂O (l) (skeleton equation: unbalanced)
Once you balance it, you get:
- C₃H₈ (g) + 5O₂(g) → 3CO₂ (g) + 4H₂O (l)
Left side Right side
C 3 3
H 8 4×2 = 8
O 5×2 = 10 3×2 + 4 = 10
That equation corresponds to the option D. of the list, with the proviso that the subscripts of propane's chemical formula must be corrected
Answer:

Explanation:
Hello,
In this case, the reaction is:

Thus, the law of mass action turns out:
![Kc=\frac{[CH_3CH_2OH]_{eq}}{[H_2O]_{eq}[CH_2CH_2]_{eq}}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BCH_3CH_2OH%5D_%7Beq%7D%7D%7B%5BH_2O%5D_%7Beq%7D%5BCH_2CH_2%5D_%7Beq%7D%7D)
Thus, since at the beginning there are 29 moles of ethylene and once the equilibrium is reached, there are 16 moles of ethylene, the change
result:
![[CH_2CH_2]_{eq}=29mol-x=16mol\\x=29-16=13mol](https://tex.z-dn.net/?f=%5BCH_2CH_2%5D_%7Beq%7D%3D29mol-x%3D16mol%5C%5Cx%3D29-16%3D13mol)
In such a way, the equilibrium constant is then:

Thereby, the initial moles for the second equilibrium are modified as shown on the denominator in the modified law of mass action by considering the added 15 moles of ethylene:

Thus, the second change,
finally result (solving by solver or quadratic equation):

Finally, such second change equals the moles of ethanol after equilibrium based on the stoichiometry:

Best regards.