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Mrrafil [7]
3 years ago
12

How does heating or cooling a substance help demonstrate the law of conservation of matter? PLS I NEED HELP ASAP ILL GIVE 5 STAR

A HEART AND BRAINLYEST
Chemistry
2 answers:
I am Lyosha [343]3 years ago
7 0

Answer:

It can help change it's form.

Explanation:

The law of conservation of matter or mass, states that matter is neither created nor destroyed. But, you can change the form of matter based o Physical and/ or Chemical changes.

Let's take water as an example.  Water is a liquid, but you can always change water into a gaseous or solid form by using heat or cooling methods. When you heat water, the molecules move faster to make it form into a gas form...... You don't change it chemically, but physically. Same as the cooling process, only this time you are changing it into a solid.

Hope this helps :D

Lapatulllka [165]3 years ago
3 0

Answer:

The Law of Conservation of Matter says that the amount of matter stays the same, even when matter changes form. Sometimes it may seem that matter disappears during a science experiment, but this law tells us that matter cannot magically appear or disappear, it simply changes from one form to another. Another way to explain the law of conservation of matter is to say that things cannot be magically created or destroyed.

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iragen [17]
I think when you unscramble it, it’s expiration.
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3 years ago
How much of a sample remains after five half-lives have occurred?
timama [110]

Answer:

1/32 of the original sample

Explanation:

We have to use the formula

N/No = (1/2)^t/t1/2

N= amount of radioactive sample left after n number of half lives

No= original amount of radioactive sample present

t= time taken for the amount of radioactive samples to reduce to N

t1/2= half-life of the radioactive sample

We have been told that t= five half lives. This implies that t= 5(t1/2)

N/No = (1/2)^5(t1/2)/t1/2

Note that the ratio of radioactive samples left after time (t) is given by N/No. Hence;

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3 0
3 years ago
Compounds A and BB are colorless gases obtained by combining sulfur with oxygen. Compound A results from combining 6.00 gg of su
Lelechka [254]

Answer:

Mass ratio of sulfur and oxygen in compounds A and B is 3:2 which confirms that the mass ratios in the two compounds are simple multiples of each other

Explanation:

This question seeks to establish/confirm the law of multiple proportions which  posits that elements combine to form different substances which are whole number multiples of each other. Best example of this plays out in the formation of several oxides of the same element. Looking at the ratio in which the elements combine in each of the oxides, we can assume that these ratios are simple whole number multiples of each other.

Now back to the question.

In substance A, we have 6 g of sulfur combining with 5.99 g of oxygen

Now, lest us calculate the ratio of the mass of sulfur to that of oxygen = 6g/5.99g = 1

Now let us calculate the mass ratio of sulfur to oxygen in the second compound = 8.6/12.88 = 0.668

Now the ratios in both compounds are 1 to 0.668. 0.668 to fraction is approximately 1/1.5.

So therefore, the ratio we are having would be 1:1/1.5 or 1:0.668

This is same as 1/(1÷1.5) which is 1.5/1 or simply 3/2

This gives a ratio of approximately 1.5 to 1 or 3 to 2

The ratio 3 to 2 indicates that the mass ratios in both com pounds are simple multiples of each other

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4 years ago
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inn [45]

Answer:

tissue

Explanation:

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3 years ago
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