Answer:
441.28 g Oxygen
Explanation:
- The combustion of hydrogen gives water as the product.
- The equation for the reaction is;
2H₂(g) + O₂(g) → 2H₂O(l)
Mass of hydrogen = 55.6 g
Number of moles of hydrogen
Moles = Mass/Molar mass
= 55.6 g ÷ 2.016 g/mol
= 27.8 moles
The mole ratio of Hydrogen to Oxygen is 2:1
Therefore;
Number of moles of oxygen = 27.5794 moles ÷ 2
= 13.790 moles
Mass of oxygen gas will therefore be;
Mass = Number of moles × Molar mass
Molar mass of oxygen gas is 32 g/mol
Mass = 13.790 moles × 32 g/mol
<h3> = 441.28 g</h3><h3>Alternatively:</h3>
Mass of hydrogen + mass of oxygen = Mass of water
Therefore;
Mass of oxygen = Mass of water - mass of hydrogen
= 497 g - 55.6 g
<h3> = 441.4 g </h3>
Answer: 173 g ( 0.17 kg in right accuracy)
Explanation: Amount in moles is n = N/Na = 2.0·10^24 / 6.022·10^23 (1/mol).
n = 3.32116 mol. M(Cr) = 52.00 g/mol and mass m = nM = 172.7 g
Between equatorial positions, the F-P-F angle is 120°, and between axial and equatorial positions, it is 90°.
<h3>What in chemical bonding is equatorial position?</h3>
Equatorial Organic Chemistry Illustrated Glossary. Equatorial: In cyclohexane, a bond that runs parallel to the ring's axis (i.e., it follows the chair's equator), or a group joined by such a bond. Positions A are axial, and positions E are equatorial.
<h3>Why do equatorial positions have greater stability?</h3>
As was said in the preceding section, the equilibrium favors the more stable conformer because the chair conformation, in which the methyl group is equatorial, lowers steric repulsion. All monosubstituted cyclohexanes share this property.
To know more about equatorial positions visit:
brainly.com/question/24168112
#SPJ4
You are given
200 grams of H2O(s) at an initial temperature of 0°C. you are also given the
final temperature of water after heating at 65°C. You are required to get the
total amount of heat to melt the sample. The specific heat capacity, cp, of
water is 4.186 J/g-°C. Let us say that T1 = 0°C and T2 = 65°C. The equation for
heat, Q, is
Q = m(cp)(T2-T1)
Q = 200g(4.186
J/g-°C )(65°C - 0°C)
<u>Q =
54,418J</u>
262. 5cm3.
using the Boyles law formula. p1v1=p2v2
P1=760torr.
v1=525cm³
p2=760×2=1520torr.
v2=?
p1v1=p2v2
760×525=1520×v2
v2=[ 760×525]÷1520
v2= 262.5cm³
when the pressure increases, the volume decreases.
