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lesya692 [45]
3 years ago
11

Heat is added to a 200.-gram sample of H2O(s) to melt the sample at 0°C. Then the resulting H2O (image) is heated to a final tem

perature of 65°C. Determine the total amount of heat required to completely melt the sample.
Chemistry
2 answers:
pochemuha3 years ago
3 0
You are given 200 grams of H2O(s) at an initial temperature of 0°C. you are also given the final temperature of water after heating at 65°C. You are required to get the total amount of heat to melt the sample. The specific heat capacity, cp, of water is 4.186 J/g-°C. Let us say that T1 = 0°C and T2 = 65°C. The equation for heat, Q, is  

Q = m(cp)(T2-T1)
Q = 200g(4.186 J/g-°C )(65°C - 0°C)
<u>Q = 54,418J</u>
MaRussiya [10]3 years ago
3 0

Answer: 54.418 kJ amount of heat required to completely melt the sample.

Explanation:

Mass of water = 200 g

Initial temperature of the water = 0°C

Final  temperature of the water = 65°C

Temperature change =\Delta T=65^oC-0^oC=65^oC

Specific heat capacity = 4.186J/g^oC

Q=mC\Delta T=200 g\times 4.186J/g^oC\times 65^oC

Q=54,418 J=54.418 kJ  (1 kJ = 1000J)

54.418 kJ amount of heat required to completely melt the sample.

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Soloha48 [4]

Answer:

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Explanation:

a. By the notation given, first is represented the oxidation reaction and then the reduction reaction, so they are:

Al(s) ⇄ Al⁺³(aq) + 3e⁻ (oxidation)

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A galvanic cell is spontaneous, so the cathode (reduction) has a higher E° than the cathode (oxidation). In this case, the oxidation reaction has a higher E°, so the reaction is nonspontaneous and it's necessary an external force to it happen, so it's an electrolytic cell.

d. 2Al(s) + 3Mg²⁺(aq) ⇄ 2Al⁺³(aq) + 3Mg(s)

The number of electrons must be the same, so the oxidation reaction is multiplied by 2, and the reduction reaction by 3.

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Answer:

See explanation

Explanation:

In this case, we have to remember that if we want to remove water from the reaction vessel we have to heat the vessel. So, we can convert the liquid water into <u>gas water</u> and we can remove it from the vessel. In this case, the products of dehydration for both molecules are <u>(E)-4-methylpent-2-ene</u> and <u>cyclohexene</u> with boiling points of <u>59.2 ºC</u> and <u>89 ºC</u> respectively. The boiling point of water is <u>100 ºC</u>, therefore if we heat the vessel the products and water would leave the system, and the products would be lost.

See figure 1

I hope it helps!

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