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Nana76 [90]
4 years ago
9

What is the symbol for Sodium Chloride? A. NaOH B. NaCl C.SbCl3 D.HCl

Chemistry
1 answer:
Ivenika [448]4 years ago
6 0

Answer:

B.

Explanation:

Na is Sodium and Cl is Chlorine [Chloride]

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A monatomic ideal gas that is initially at 1.50 * 105 Pa and has a volume of 0.0800 m3 is compressed adiabatically to a volume o
lubasha [3.4K]

Answer:

300000Pa or 3×10^5 Pa

Explanation:

Since the problem involves only two parameters of volume and pressure, the formula for Boyle's law is suitably used.

Using Boyle's law

P1V1 = P2V2

P1 is the initial pressure = 1.5×10^5Pa

V1 is the initial volume = 0.08m3

P2 is the final pressure (required)

V2 is the final volume = 0.04 m3

From the formula, P2 = P1V1/V2

P2 = 1.5×10^5 × 0.08 ÷ 0.04

= 300000Pa or 3×10^5 Pa.

8 0
3 years ago
What is the group number of the most metallic group that contains metalloids?
LUCKY_DIMON [66]
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7 1
3 years ago
Read 2 more answers
A potassium iodide compound is represented by which formula?
andrew11 [14]
It is represented by C) KI

K+
I-

So it's KI
7 0
4 years ago
Read 2 more answers
Que es la tabla periodica, que organiza y para que se utiliza
VladimirAG [237]

Answer:

La tabla periódica, también conocida como la tabla periódica de elementos, es una visualización tabular de los elementos químicos, que están organizados por número atómico, configuración electrónica y propiedades químicas recurrentes. La estructura de la tabla muestra tendencias periódicas.

Explanation:

google definition

3 0
4 years ago
N2O4(g) + 4H2(g) → N2(g) + 4H2O(g), solve using standard enthalpies of formation
aev [14]

The standard enthalpy of formation (ΔH_f) is a measure of the energy released or consumed when one mole of a substance is created under standard conditions from its pure elements.

Standard enthalpies (ΔH_f) of formation for given reaction is 978.3 kJ

<h3>What is Standard enthalpies of formation?</h3>

The standard enthalpy of formation is defined as the enthalpy change when one mole of a substance in the standard state (1 atm of pressure and 298.15 K) is formed from its pure elements under the same conditions.

Given reaction ;

N_2O_4(g) + 4H_2 (g) - > N_2(g) + 4H_2O(g)

To Find : ΔH_f

ΔH_f = ∑np ΔH_f (products) – ∑np ΔH_f (reactants)

ΔH_f = [1(ΔH_f N_2) + 4(ΔH_f H_2O)] – [1(ΔH_f N_2O_4) + 4(ΔH_f H_2)]

ΔH_f = [1(0) + 4(-241.8)] – [1(+9.16) + 4(0)]

ΔH_f  = [4(-241.8)] – [1(+9.16)] = 978.3 kJ

Learn more about Enthalpy here ;
brainly.com/question/16720480

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7 0
2 years ago
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