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mr Goodwill [35]
3 years ago
12

How many grams of nacl are in 250 g of a 15.0% (by weight) solution?

Chemistry
1 answer:
Gelneren [198K]3 years ago
4 0

Answer: -

37.5 g of NaCl are in 250 g of a 15.0% (by weight) solution.

Explanation: -

Total mass = 250 g

Percentage of NaCl = 15.0 %

= \frac{Number of grams of NaCl present}{total mass}

Thus \frac{15}{100} = \frac{Number of grams of NaCl present}{250g}

Number of grams of NaCl present = \frac{15 x 250g}{100}

= 37.5 g

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Use the following half-reactions to write three spontaneous reactions, calculate E°cell for each reaction, and rank the oxidizin
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Answer:

See explaination

Explanation:

1)

we know that

half cell with higher reduction potential is cathode

so

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anode :

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so

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now

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so

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now

in this case

oxidizing agents are N20 and Cr+3

reducing agents are Cr and N2

higher the reduction potential , stronger the oxidizing agent

lower the reduction potential , stronger the reducing agent

so

oxidzing agents

N20 > Cr+3

reducing agents

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2)

cathode :

Au+ + e- --> Au

anode :

Cr ---> Cr+3 + 3e-

overall reaction

3Au+ + Cr ---> 3Au + Cr+3

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now

oxidizing agents :

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reducing agents :

Cr > Au

3)

cathode :

N20 + 2H+ + 2e- ---> N2 + H20

andoe :

Au ---> Au+ + e-

overall

2 Au + N20 + 2H+ --> 2 Au+ + N2 + H20

Eo cell = 1.77 - 1.69

Eo cell = 0.08

oxidizing agents

N20 > Au+

reducing agents

Au > N2

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<h3>Further explanation</h3>

Given

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Required

Type of reaction

Solution

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