Answer:It will be larger and uprightIt will be larger and uprightupright ,,
Explanation:The image shows that the object (in this case it's candle) is in between the focal point and the mirror itself. In this case the one ray which is parallel to the mirror axis will pass through the focal point where as the second ray will first pass through the focal point and then touches the tip of the candle. If we extend the two rays behind the mirror, we will get the larger and upright image behind the mirror (as shown in the image attached with this post). Hence correct option is (C): It will be larger and upright.
<span>After collison they stick together and have same velocity Vf
From the momentum conservation,
(m1 + m2)Vf = m1v1 + m2v2
Second is moving with half of first cart speed, (m1 + m2)Vf = m1v + m2v / 2
2(m1 + m2)Vf = (2m1v + m2v) =>Vf = ((2m1 + m2) v) / 2(m1 + m2)
Identical carts so m1 = m2 = m
vf = 3mv / 4m => Vf = 3v / 4</span>
(since you asked for basic understanding only, I am not including actual calculations. Please let me know in the comments section if you wish to verify your solution(s))
For (b): Use the formula for distance (s) made during an accelerated motion:
with v_0 and s_0 being the initial velocity and distance, both 0 in this case, and with "a" denoting the acceleration, in this case solely due to gravitational acceleration so: "g."
You are given the distance made, namely 10 m, and the duration t (0.88s) and so using the formula above you can solve for g.
For (c), to determine the final velocity at time 0.88s use the formula for the instantaneous velocity of an accelerated motion
(velocity at time t) = (acceleration) x (time)
again, with acceleration due to gravity, i.e., a = g and with g as determined under (b).
If my calculation is correct, this mystery planet could be the Jupiter.
Answer:
v = 17.9 m/s
Explanation:
As we know that the normal force measured by the sensor before the ride is started is given as
now when the rider has reached at the top position of the loop then the normal force is given as
now at the top position we have
so we have