Answer:
(a) 0.2618 J
(b) 0.1558 J
(c) 0 J
Explanation:
from Hook's Law,
The energy stored in a stretched spring = 1/2ke²
Ep = 1/2ke² ......................... Equation 1
Where k = spring constant, e = extension, E p = potential energy stored in the spring.
(a) When The spring is stretched to 4.11 cm,
Given: k = 310 N/m, e = 4.11 cm = 0.0411 m
Substituting these values into equation 1
Ep = 1/2(310)(0.0411)²
Ep = 155(0.0016892)
Ep =155×0.0016892
Ep = 0.2618 J.
(b) When the spring is stretched 3.17 cm
e = 3.17 cm = 0.0317 m.
Ep = 1/2(310)(0.0317)²
Ep = 155(0.0317)²
Ep = 155(0.0010049)
Ep = 0.155758 J
Ep ≈ 0.1558 J.
(c) When the spring is unstretched,
e = 0 m, k = 310 N/m
Ep = 1/2(310)(0)²
Ep = 0 J.
Answer:
734.16 kg m/
Explanation:
The problem is asking for the Force of pushing off the ground.
- The formula of Force is: F = mass x acceleration
Given = <em>Mass</em>: 600 newtons (N)
<em>Acceleration</em>: 12 m/
We have to convert the mass into kg first. Remember that <u>1 kg is equal to 9.80665 newtons.</u>
Let x be the<em> mass in newtons</em>.
Let's convert: 
x 
= 
= 61.18 kg
Phil's weight is 61.18 kg
Let's go back to finding the force.
F = m x a
F = 61.18 kg x 12 m/
F = 734.16 kg m/
Answer:
the time at which it passes through the equilibrum position is:
t = 0.1 second
Explanation:
given
w= 4pounds
k(spring constant) = 2lb/ft
g(gravitational constant) = 10m/s² = 32ft/s²
β(initial point above equilibrum) = 1
velocity = 14ft/s
attached is an image showing the calculations, because some of the parameters aren't convenient to type.
Answer:
The greater the amount of output for a given unit of input, the higher the overall productivity. Businesses generally aim to improve productivity over time to maintain competitiveness and increase the business's profitability. Individuals are familiar with the idea of productivity in their own lives.
B. Primary target market , because its a business ( you sell in a business ) and it says a certain group which would be a target.
