The final velocity of the truck is found as 146.969 m/s.
Explanation:
As it is stated that the lorry was in standstill position before travelling a distance or covering a distance of 3600 m, the initial velocity is considered as zero. Then, it is stated that the lorry travels with constant acceleration. So we can use the equations of motion to determine the final velocity of the lorry when it reaches 3600 m distance.
Thus, a initial velocity (u) = 0, acceleration a = 3 m/s² and the displacement s is 3600 m. The third equation of motion should be used to determine the final velocity as below.
![2as =v^{2} - u^{2} \\\\v^{2} = 2as + u^{2}](https://tex.z-dn.net/?f=2as%20%3Dv%5E%7B2%7D%20-%20u%5E%7B2%7D%20%5C%5C%5C%5Cv%5E%7B2%7D%20%3D%202as%20%2B%20u%5E%7B2%7D)
Then, the final velocity will be
![v^{2} = 2 * 3 * 3600 + 0 = 21600\\ \\v=\sqrt{21600}=146.969 m/s](https://tex.z-dn.net/?f=v%5E%7B2%7D%20%3D%202%20%2A%203%20%2A%203600%20%2B%200%20%3D%2021600%5C%5C%20%5C%5Cv%3D%5Csqrt%7B21600%7D%3D146.969%20m%2Fs)
Thus, the final velocity of the truck is found as 146.969 m/s.
C. nervous system, because its triggers
The position of the object at time t =2.0 s is <u>6.4 m.</u>
Velocity vₓ of a body is the rate at which the position x of the object changes with time.
Therefore,
![v_x= \frac{dx}{dt}](https://tex.z-dn.net/?f=v_x%3D%20%5Cfrac%7Bdx%7D%7Bdt%7D)
Write an equation for x.
![dx=v_xdt\\ x=\int v_xdt](https://tex.z-dn.net/?f=dx%3Dv_xdt%5C%5C%20x%3D%5Cint%20v_xdt)
Substitute the equation for vₓ =2t² in the integral.
![x=\int v_xdt\\ =\int2t^2dt\\ =\frac{2t^3}{3} +C](https://tex.z-dn.net/?f=x%3D%5Cint%20v_xdt%5C%5C%20%3D%5Cint2t%5E2dt%5C%5C%20%3D%5Cfrac%7B2t%5E3%7D%7B3%7D%20%2BC)
Here, the constant of integration is C and it is determined by applying initial conditions.
When t =0, x = 1. 1m
![x= \frac{2t^3}{3} +C\\ x_0=1.1\\ x= (\frac{2t^3}{3} +1.1)m](https://tex.z-dn.net/?f=x%3D%20%5Cfrac%7B2t%5E3%7D%7B3%7D%20%2BC%5C%5C%20x_0%3D1.1%5C%5C%20x%3D%20%28%5Cfrac%7B2t%5E3%7D%7B3%7D%20%2B1.1%29m)
Substitute 2.0s for t.
![x= (\frac{2t^3}{3} +1.1)m\\ =\frac{2(2.0)^3}{3} +1.1\\ =6.43 m](https://tex.z-dn.net/?f=x%3D%20%28%5Cfrac%7B2t%5E3%7D%7B3%7D%20%2B1.1%29m%5C%5C%20%3D%5Cfrac%7B2%282.0%29%5E3%7D%7B3%7D%20%2B1.1%5C%5C%20%3D6.43%20m)
The position of the particle at t =2.0 s is <u>6.4m</u>
Answer: Rn :)))) no explanation needed
Answer:
its B because we're not talking about mass even tho most people would have chosen A cuz it says mass and u they would think its apart of density but if ur testing to see density ur figuring out which object will sink and which one will float so da reason why da penny snuck it cuz da density is greater den da water and copper has a better chance of sinking den floating so dats why its B I hope dis helps :3