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EastWind [94]
3 years ago
6

What is the solution to the following equation?

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
3 0

Answer:

x = 4

Step-by-step explanation:

8x - 9 = 6x - 1

Bring variables to the left side, whereas numbers to the right.

8x - 6x = - 1 + 9

2x = 8

x = 8 / 2

x = 4

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Gilberto’s grandfather gives him $5 for his birthday and then $.50 for each math question he answers correctly on his math exams
Alexandra [31]

Answer:

<h3>Therefore total amount of money that he got is = $(5+0.50x)   [ x = number of correct math]</h3>

Step-by-step explanation:

Given, Gilberto's grandfather gives him $5 for his birthday and then$0.50 for each math he answers correctly on his math exam for the year.

Let , the number of math that he answers correctly on his his math exam for the year is x

Therefore he got = $(0.50× x) =$ 0.50x for doing correct math.

Therefore total amount of money that he got is = $(5+0.50x)   [ x = number of correct math]

5 0
4 years ago
The operation manager at a tire manufacturing company believes that the mean mileage of a tire is 44,663 miles, with a standard
expeople1 [14]

Answer:

The probability is  P(| \= X- \mu|  < 199 ) = 0.733

Step-by-step explanation:

From the question we are told that

   The mean mileage of a tire is   \mu =  44663

   The standard deviation is  \sigma  =  2594

   The sample size is  n  =  209

 Generally the standard error of mean is mathematically represented as

    \sigma_{x}  =  \frac{\sigma}{\sqrt{n} }

=>  \sigma_{x}  =  \frac{2594}{\sqrt{209} }  

=>  \sigma_{x}  =   179.4      

Generally  the probability that the sample mean would differ from the population mean by less than 199 miles  is mathematically represented as

     P(| \= X- \mu| < 199 ) = P(|\frac{\= X - \mu}{ \sigma_{x}}|  <  \frac{199}{ 179.4})

\frac{\= X -\mu}{\sigma }  =  Z (The  \ standardized \  value\  of  \ \= X )

=>  P(| \= X- \mu|  < 199 ) = P(|Z|  <  \frac{199}{ 179.4})

=>   P(| \= X- \mu|  < 199 ) = P(|Z|<  1.11)

=>   P(| \= X- \mu| < 199 ) = P(-1.11  \le  Z \le 1.11 )

=>   P(| \= X- \mu|  < 199 ) = P(Z  \le 1.11 ) - P( Z \le -1.11 )

From the z  table  the area under the normal curve to the left corresponding to 1.11 and -1.11 is  

        P(Z  \le 1.11 ) = 0.8665

and

       P(Z  \le - 1.11 ) = 0.1335

So

    P(| \= X- \mu| < 199 ) = 0.8665 - 0.1335

=>  P(| \= X- \mu|  < 199 ) = 0.733

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3 years ago
The exponential function g(t)=500(1-3^-t) describes how long it takes for a population of 500 catfish to migrate from a holding
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What is the question bro or gal
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Find the next two numbers in the pattern -128,64,-32,16
Tems11 [23]

Answer:

Step-by-step explanation:-8

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You leave a 12% tip for a $25 meal. How much is the tip, in dollars?
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Answer:

3 dollars

Step-by-step explanation: divide 25 by .12=3.00

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