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EastWind [94]
3 years ago
6

What is the solution to the following equation?

Mathematics
1 answer:
Pachacha [2.7K]3 years ago
3 0

Answer:

x = 4

Step-by-step explanation:

8x - 9 = 6x - 1

Bring variables to the left side, whereas numbers to the right.

8x - 6x = - 1 + 9

2x = 8

x = 8 / 2

x = 4

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2 years ago
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Which graphs have rotational symmetry? Check all of the boxes that apply.
ivanzaharov [21]

Answer:

The correct option are;

On a coordinate plane, a cubic function has an x-intercept of (0, 0)

On a coordinate plane, an oval is in quadrant 1

Step-by-step explanation:

Rotational symmetry of a shape is a shape that when it is rotated on its axis to a given angle less than one complete revolution, the shape looks exactly like the pre-image or original appearance of the shape

For a cubic function that has x-intercept = (0, 0) we have;

y = f(x) = a·x³ + b·x² + c·x

Has the shape f a fan blade and therefore, looks the sane when rotated when rotated through 180°

The shape of an oval looks the same when rotated through 180°

8 0
3 years ago
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the faster a vehicle is going, the further it will continue to travel after the brakes are applied. Which is the independent var
nevsk [136]
I believe that the answer is speed in this situation but I'm not 100% sure
3 0
3 years ago
A shade of yellow light with a wavelength of 5.8×10-7 m and a frequency of 5.17 × 10-14 Hz
harina [27]

Step-by-step explanation:

We have,

The wavelength of yellow light, \lambda=5.8\times 10^{-7}\ m

Frequency of yellow light, f=5.17\times 10^{-14}\ Hz

It is assumed to find the speed of light in the yellow light.

The speed of a wave is given in terms of wavelength and frequency as :

v=f\lambda\\\\v=5.17\times 10^{-14}\times 5.8\times 10^{-7}\\\\v=2.99\times 10^{-20}\ m/s

So, the speed of light in a shade of yellow light is 2.99\times 10^{-20}\ m/s.

4 0
3 years ago
A bag contains 11 blocks numbered from 1 to 11. Two blocks are selected from the bag at the same time. (order does not matter) L
melamori03 [73]

Answer:

(A) n(Eᶜ)=40

Step-by-step explanation:

The Sample Space for is given as:

(1,2),(1,3),(1,4),(1,5),(1,6),(1,7),(1,8),(1,9),(1,10),(1,11)

(2,3),(2,4),(2,5),(2,6),(2,7),(2,8),(2,9),(2,10),(2,11)

(3,4),(3,5),(3,6),(3,7),(3,8),(3,9),(3,10),(3,11)

(4,5),(4,6),(4,7),(4,8),(4,9),(4,10),(4,11)

(5,6),(5,7),(5,8),(5,9),(5,10),(5,11)

(6,7),(6,8),(6,9),(6,10),(6,11)

(7,8),(7,9),(7,10),(7,11)

(8,9),(8,10),(8,11)

(9,10),(9,11)

(10,11)

n(S)=55

Event E is the Event that the two numbers are odd.

Therefore: Complement of E will be the event that any of the  two numbers is even.

The Sample Space of the complement of E is:

(1,2),(1,4),(1,6),(1,8),(1,10)\\(2,3),(2,4),(2,5),(2,6),(2,7),(2,8),(2,9),(2,10),(2,11)\\(3,4),(3,6),(3,8),(3,10)\\(4,5),(4,6),(4,7),(4,8),(4,9),(4,10),(4,11)\\(5,6),(5,8),(5,10)\\(6,7),(6,8),(6,9),(6,10),(6,11)\\(7,8),(7,10)\\(8,9),(8,10),(8,11)\\(9,10)\\(10,11)\\

Therefore:

n(Eᶜ)=40

5 0
3 years ago
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