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lisov135 [29]
3 years ago
11

What is the solution set of 2x2+x=15?

Mathematics
2 answers:
vodomira [7]3 years ago
7 0
4+x=15
---> x=15-4
---> x=11
Alexeev081 [22]3 years ago
5 0

Answer:

5/2,-3

Step-by-step explanation:

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Jeremy had 5 Roosevelt dimes, 3 Kennedy half dollars, and 8 silver dollars in his coin collection worth a total of $231.
andre [41]
The linear equation would be, 5d + 3h + 8s = 231
4 0
3 years ago
Which expression is NOT equivalent to 6m +18?
Varvara68 [4.7K]

Answer:6+m+18

Step-by-step explanation: 6+m=7m so 7m+18 would be wrong. Hope it helps!

5 0
3 years ago
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Initially, Greg has a total of 60 DVDs and CDs in his collection. He then sold 1/8 of his CDs and 1/2 of his DVDs. If the number
poizon [28]

Answer:

10 DVD's were sold.

Step-by-step explanation:

c = number of CD's

d = number of DVD's

so we know:

c + d = 60

2*c/8 = d/2

this can be solved:

d = 60 - c

2c / 8 = (60-c)/2

4*(2c/8) = 4*(60-c)/2    [multiply by 4]

c = 120 - 2c

3c = 120

c = 40

d = 60-40 = 20

So Greg had 40 CD's and 20 DVD's. He sold half of his DVD's, i.e., 20/2=10 and 1/8 of his CD, i.e., 40/8 = 5

5 0
3 years ago
A full can of vegetable broth is 17 cm tall and has a radius of 5 cm. Morgan uses some of the broth to make curry and now the br
timofeeve [1]

Answer: Morgan used aproximately 392.5 cm^3

To solve this, we calculate the voluime of the full can and then subtract the amount of broth remaining

Full can: we use the formula for the volume of a cillinder

\pi r^2h=\pi(5cm)^2\cdot17\operatorname{cm}=\text{ 1334.5}cm^3

Where r is the radius of the can and h the height. In this case, we use 17cm becouse the can is full

Remainning broth: again we use the volume of a cillinder, but in this case we use the height of the reamining broth (12 cm)

\pi r^2h=\pi(5\operatorname{cm})^2\cdot12\operatorname{cm}=942\operatorname{cm}

Now we do the full can minus the remaining broth:

1334.5\operatorname{cm}-942\operatorname{cm}=392.5\operatorname{cm}^3

And thats the amount of broth used

3 0
1 year ago
Find the number of 4-digit numbers that contain b at least three odd digits.
melamori03 [73]

Answer:

  3000

Step-by-step explanation:

There are 5 odd digits, so 5^3 = 125 ways to have 3 odd digits.

Given 3 odd digits, the first digit can be even, but not zero, so there are 4 ways to do that.

The second, third, or fourth digits can be even 5 ways, so there are ...

  125(4 +5 +5 +5) = 2375

ways to have 3 odd digits in a 4-digit number.

__

There are 5^4 = 625 ways to have 4 odd digits.

The number of 4-digit numbers with 3 or 4 odd digits is ...

  2375 +625 = 3000

6 0
3 years ago
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