S is the set of prime numbers that are less than 15. The correct solution in roster form is {1,3,5,7,9,11,13}. The answer is letter C. The rest of the choices do not answer the question above.
Answer:
![$\[x^2 + 22x + 121\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20121%5C%5D%24)
Step-by-step explanation:
Given
![$\[x^2 + 22x + \underline{~~~~}.\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20%5Cunderline%7B~~~~%7D.%5C%5D%24)
Required
Fill in the gap
Represent the blank with k
![$\[x^2 + 22x + k\]$](https://tex.z-dn.net/?f=%24%5C%5Bx%5E2%20%2B%2022x%20%2B%20k%5C%5D%24)
Solving for k...
To do this, we start by getting the coefficient of x
Coefficient of x = 22
<em />
Divide the coefficient by 2
Take the square of this result, to give k
Substitute 121 for k
The expression can be factorized as follows;
<em>Hence, the quadratic expression is </em><em></em>
Answer:
True, A
Step-by-step explanation:
If you sum two different sides of a traingle it must be greater than the remaining one
We can test that by adding the two smallest sides
1+8=9
9 is obviously greater than 8, so the answer is: true
Answer:
-1.
Step-by-step explanation:
1/m = m^-1.
We can show this is correct if we simplify the following:
m^2 / m ^3 = m * m / m * m* m = 1/m
By the law of indices: m ^2 / m^3 = m^(2-3) = m^-1.
