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2 years ago

If you earn $48,000 per year, how much will you receive on a biweekly basis?

Mathematics

2 answers:

Vitek1552 [10]2 years ago

7 0

Answer:

$48,000 ÷ 26 = $1,846.15

I hope this helps!!

Harrizon [31]2 years ago

5 0

$48,000 a year is $1,846.15 biweekly before taxes and approximately $1,384.62 after taxes. Paying a tax rate of around 25% and working full-time at 40 hours a week, you would earn $1,384.62 after taxes. To calculate how much you make biweekly before taxes, you would multiply $23.08 by 40 hours and 2 weeks

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2 years ago

Star Wars land encompasses an area of 14.0 acres. [1.00 acre = 4046.86m2]. If Star Wars land were made into a circle, what would

Free_Kalibri [48]

Answer:

<h3>The answer is 134.29 m</h3>

Step-by-step explanation:

First of all we need to convert 14.0 acres to m²

1.00 acre = 4046.86 m²

14.0 acres = 14 × 4046.86 = 56656.04 m²

Area of a circle = πr²

where

r is the radius

To find the radius substitute the value for the area into the above formula and solve for the radius

That's

$56656.04 = \pi {r}^{2}$

Divide both sides by π

We have

${r}^{2} = \frac{56656.04}{\pi}$

Find the square root of both sides

$r = \sqrt{ \frac{56656.04}{\pi} }$

r = 134.29139

r = 134.29 m to 2 decimal places

Hope this helps you

3 0

2 years ago

Solve the system of equations using substitution.

faltersainse [42]

Answer:

( $\frac{1}{3}$ , 3 )

Step-by-step explanation:

Given the 2 equations

y = 9x → (1)

6x - y = - 1 → (2)

Substitute y = 9x into (2)

6x - 9x = - 1, that is

- 3x = - 1 ( divide both sides by - 3 )

x = $\frac{1}{3}$

Substitute x = $\frac{1}{3}$ into (1) for corresponding value of y

y = 9 × $\frac{1}{3}$ = 3

Solution is ( $\frac{1}{3}$ , 3 )

6 0

2 years ago

In a research laboratory, a scientist measures the mass of a 1-carat diamond and finds it to be 200 milligrams, measured to the

vlada-n [284]

Answer:

$D=3.5\ gr/cm^3$

Step-by-step explanation:

<u>Density</u>

The density of an object of mass m and volume V is given by

$\displaystyle D=\frac{m}{V}$

It can be expressed in common units like $gr/lt, Kg/m^3, gr/cm^3$ or any other combination of proper mass [M] by volume [V] units.

The data provided in the question is

$m=200\ mg = 0.2\ gr$

$V=0.057\ cm^3$

Thus, the measured density is

$\displaystyle D=\frac{0.2\ gr}{0.057 \ cm^3}$

$\boxed{D=3.5\ gr/cm^3}$

We have expressed the result with 1 decimal place because the mass was measured to the nearest hundred milligrams (or one-tenth grams). Any further decimal is senseless because that precision comes from calculations, not from measurements.

6 0

2 years ago

Need help with homework

motikmotik

We have two points describing the diameter of a circumference, these are:

$\begin{gathered} A=(-12,-4) \\ B=(-4,-10) \end{gathered}$

Recall that the equation for the standard form of a circle is:

$(x-h)^2+(y-k)^2=r^2$

Where (h,k) is the coordinate of the center of the circle, to find this coordinate, we find the midpoint of the diameter, that is, the midpoint between points A and B.

For this we use the following equation:

$M=(\frac{x_1+x_2_{}_{}}{2},\frac{y_1+y_2}{2})$

Now, we replace and solve:

$\begin{gathered} M=(\frac{-12+(-4)}{2},\frac{-4+(-10)}{2} \\ M=(\frac{-12-4}{2},\frac{-4-10}{2}) \\ M=(\frac{-16}{2},\frac{-14}{2}) \\ M=(-8,-7) \end{gathered}$

The center of the circle is (-8,-7), so:

$\begin{gathered} h=-8 \\ k=-7 \end{gathered}$

On the other hand, we must find the radius of the circle, remember that the radius of a circle goes from the center of the circumference to a point on its arc, for this we use the following equation:

$r^2=\Delta x^2+\Delta y^2$

In this case, we will solve the delta with the center coordinate and the B coordinate.

$\begin{gathered} r^2=((-4)-(-8))^2+((-10)-(-7)) \\ r^2=(-4+8)^2+(-10+7)^2 \\ r^2=4^2+(-3)^2 \\ r^2=16+9 \\ r^2=25 \\ r=5 \end{gathered}$

Therefore, the equation for the standard form of a circle is:

$\begin{gathered} (x-(-8))^2+(y-(-7))^2=25 \\ (x+8)^2+(y+7)^2=25 \end{gathered}$

In conclusion, the equation is the following:

$(x+8)^2+(y+7)^2=25$

4 0

8 months ago