4 years ago

Solve for x. 1/2x=20 Pleasse Helllp Thankss Choices 140 110 10 40

Mathematics

2 answers:

Svetradugi [14.3K]4 years ago

7 0

1/2x = 20
x = 20 / (1/2)
x = 20 * 2/1
x = 40 <==

posledela4 years ago

5 0

Ur answer is 40 (1/2 * 40 = 40/2) 40 divided by 2 = 20

You might be interested in

Given that y c1 c2x2 is a two-parameter family of solutions of xy y 0 on the interval ( , ), show that constants c1 and c2 canno

hammer [34]

Answer: no solution

Step-by-step explanation: see attachment

5 0

3 years ago

When ____________, change the second number to the opposite and then add

nata0808 [166]

Answer:

Subtracting a negative number

7 0

3 years ago

Which method could be used to prove they are similar?<br> 1.5<br> 3<br> 4.5<br> Jy

Veronika [31]

Answer:

Prove what is similar?????

5 0

3 years ago

PLEASE HELP SOON!!!!!!!!

MA_775_DIABLO [31]

Answer:

8xh>168, and h>21.

Step-by-step explanation:

I took this quiz.

4 0

3 years ago

Read 2 more answers

The water height of a pool is determined by 5g2 + 3g − 2, the rate that the pool is filled, and 6g2 − 4g − 3, the rate that wate

lyudmila [28]

Answer:

$h_g=-g^2+7g+1\\\\h_1=7\\\\h_2=11\\\\h_3=13\\\\h_4=13$

Step-by-step explanation:

Given the rate of filling is $5g^2+3g-2$ and the rate of emptying the pool is $6g^2-4g-3$ . The height of the pool at any time is:

$h_t=R_{in}-R_{out}, h_t- \ height \ at\ time\ t\\\\h_t=(5g^2+3g-2)-(6g^2-4g-3)\\\\h_t=-g^2+7g+1$

#Substitute the value of g in the height equation to find the height of the pool:

#g=1

$h_t=-g^2+7g+1, \ g=1\\\\h_t=-(1)^2+7(1)+1\\\\=7$

#g=2

$h_t=-g^2+7g+1, \ g=1\\\\h_t=-(2)^2+7(2)+1\\\\=11$

#g=3

$h_t=-g^2+7g+1, \ g=1\\\\h_t=-(3)^2+7(3)+1\\\\=13$

#g=4

$h_t=-g^2+7g+1, \ g=1\\\\h_t=-(4)^2+7(4)+1\\\\=13$

6 0

4 years ago