What's the area of a rectangle measuring 13in × 12in

3 Dakota has a mirror in the shape of a trapezoid. She

borishaifa [10]

The Renaissance set the principle that "Man is the measure of all things". As a consequence, there was a growing interest in the development of humankind in all fields. In order for this to happen, improvements in education and intelligence were crucial. As a product of this growing importance of education, that Humanism was founded. Humanism is known as a stance that emphasizes the value of all human beings.

8 0

3 years ago

What percent of 8.2 is 20.5?

charle [14.2K]

250 percent of 8.2 is 20.5

8 0

3 years ago

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What is estimate 353+328

Dahasolnce [82]

If you want to estimate to the tens, the answer is 680
If you want to estimate to the hundreds, the answer is 700
If you want to estimate to the thousands then the answer would be not an answer
The real answer without estimating is 681

6 0

2 years ago

Read 2 more answers

What is 95% off $780

gogolik [260]

Answer:39

Step-by-step explanation:

5 0

3 years ago

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Several years ago, 50% of parents who had children in grades K-12 were satisfied with the quality of education the students r

galina1969 [7]

Answer:

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

We have to see if 50% = 0.5 is part of the confidence interval.

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

For this problem, we have that:

$n = 1095, \pi = \frac{478}{1095} = 0.4365$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 - 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4118$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.4365 + 1.96\sqrt{\frac{0.4365*0.5635}{1095}} = 0.4612$

The 95% confidence interval for the proportion of parents that are satisfied with their children's education is (0.4118, 0.4618). 0.5 is not part of the confidence interval, so this represents evidence that parents' attitudes toward the quality of education have changed.

5 0

2 years ago