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hjlf
3 years ago
13

From the table below, determine whether the data shows an exponential function. Explain why or why not.

Mathematics
1 answer:
Ierofanga [76]3 years ago
8 0
X        Δx                                   y             Δy

3                                               1          

1        1 - 3 = - 2                        2             2 - 1 = 1

-1        -1 - 1 = -2                      3              3 - 2 = 1

-3        -3 - (-1) = -2                  4               4 - 3 = 1


So, as you see y in increasing in regular constant intervals, when x also increases in regular constant intervals. => Δy / Δx = constant.

That is the result of a linear function, not an exponential one.

So, the true statement is given by the option <span>(A) No; the domain values are at regular intervals and the range values have a common sum 1. </span>
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Angles ABC and DBE are vertical angles where m∠ABC = (5x + 5)° and m∠DBE = (6x − 3)°.
Solnce55 [7]
Value of x when angles ABC and DBE are vertical angles where
M_ABC=(5x+ 5)° and m_DBE=(6x-3)° is 8°.
Vertical angles are complementary as there sum is 90°.
As given,
Part A:
Angles ABC and DBE are vertical angles m_ABC=(5x + 5)°
M¿DBE=(6x- 3)°
(5x+ 5\°=(6x - 31
=(6x - 5x)°=(5 +3)°
8°
Part B:
Vertical angles are complementary if there sum is 90°.
Here
m_ABC + m_DBE
5(8)+5 +6(8)-31°
= 90°
8 0
1 year ago
Please help
Ymorist [56]

Part C:

y = total cost

M = minutes


You can talk on the phone only 100 minutes per month

Company A:

y = 0.04M + 5

y = 0.04(100) + 5

y = 4 + 5

y = 9             $9 per month


Company B:

y = 0.10M + 2

y = 0.10(100) + 2

y = 10 + 2

y = 12          $12 per month


Company A offers the best deal because at Company A you have to pay $9 for 100 minutes per month, and at Company B you have to pay $12 for 100 minutes per month, so you have to pay $3 less.


Part D:

1.) With a budget of $30, Company A would allow me to talk longer on the phone. I know this because for Company A, you pay $3 less per month for the same amount of minutes as Company B. This means that I will save more money with Company A, and I can buy more minutes. (something like this)


6 0
3 years ago
Emma invested $41,000 in an account paying an interest rate of 2.6% compounded monthly. Assuming no deposits or withdrawals are
kvasek [131]

Answer: it will take 7 years for the value of the account to reach $49,300

Step-by-step explanation:

We would apply the formula for determining compound interest which is expressed as

A = P(1 + r/n)^nt

Where

A = total amount in the account at the end of t years

r represents the interest rate.

n represents the periodic interval at which it was compounded.

P represents the principal or initial amount deposited

From the information given,

P = $41000

A = $49300

r = 2.6% = 2.6/100 = 0.026

n = 12 because it was compounded 12 times in a year.

Therefore,

49300 = 41000(1 + 0.026/12)^12 × t

49300/41000 = (1 + 0.0022)^12t

1.2024 = (1.0022)^12t

Taking log of both sides of the equation, it becomes

Log 1.2024 = 12t × log 1.0022

0.08 = 12 × 0.00095 = 0.0114t

t = 0.08/0.0114

t = 7 years

8 0
3 years ago
Choose the line that is the best fit for the data.
Svet_ta [14]

Answer:

I would say line 2

Step-by-step explanation:

just think it is

3 0
2 years ago
Given that T is the centroid of △DEF and FT=12
dlinn [17]

The centroid of a triangle divides the median of the triangle into 1 : 2

The measure of FQ is 18, while the measure of TQ is 6

Because point T is the centroid, then we have the following ratio

\mathbf{TQ : FT =1 : 2}

Where FT = 12.

Substitute 12 for FT in the above ratio

\mathbf{TQ : 12 =1 : 2}

Express as fraction

\mathbf{\frac{TQ }{ 12} =\frac{1 }{ 2}}

Multiply both sides by 12

\mathbf{TQ =\frac{1 }{ 2} \times 12}

This gives

\mathbf{TQ =\frac{1 2}{ 2}}

Divide 12 by 2

\mathbf{TQ =6}

The measure of FQ is calculated using:

\mathbf{FQ = FT + TQ}

Substitute 12 for FT, and 6 for TQ

\mathbf{FQ = 12 + 6}

Add 12 and 6

\mathbf{FQ = 18}

Hence, the measure of FQ is 18, while the measure of TQ is 6

Read more about centroids at:

brainly.com/question/11891965

6 0
2 years ago
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