Answer:
23.27 L
Explanation:
The balanced reaction of ammonia and nitrogen monoxide is shown below as:
4NH₃(g) + 6NO(g) ⇒ 5N₂(g) + 6H₂O(l)
Given that:
Volume of nitrogen monoxide = 34.9 L
Since, temperature and pressure are same, volume coefficients would be same as equation coefficients.
So,
6 L of nitrogen monoxide reacts with 4 L of ammonia.
1 L of nitrogen monoxide reacts with 4/6 L of ammonia.
34.9 L of nitrogen monoxide reacts with (4/6)*34.9 L of ammonia.
Amount of ammonia required = 23.27 L