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3 years ago

What is the value of the rational expression below when x is equal to 4

Mathematics

2 answers:

Tomtit [17]3 years ago

4 0

$\cfrac{x+20}{x+4}= \cfrac{4+20}{4+4}= \cfrac{24}{8}= 3$

Zanzabum3 years ago

3 0

$\displaystyle \frac{4+20}{4+4}= \frac{24}{8}=3$

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Solve for x:<br> 4(1 – x) + 2 x = -3( x + 1)

valentinak56 [21]

Answer:

first do 4 time 1= 4

then do 4 times x =4x

now the equation should look like this

4-4x+2x=-3(x+1)

then do the other side of the equation

-3(x+1)

=-3x-3

Now collect the like terms:

-4x-2x

now the equation should look like this

4-2x=-3x-3

now add 3x add on both sides

4-2x+3x=-3

put the 4 on the other side

-2x+3x=-3-4

now again collect the like terms (-2x+3x=1 which is just x and -3-4 =-7)

x=-7

answer

x=-7

3 0

2 years ago

Read 2 more answers

You have 8 cups of flour. A recipe calls for 2/3cup of flour. Another recipe calls for 1/4 cup of flour. How much flour do you h

Sonja [21]

There will be 5 more because 8-2-1 =5

6 0

3 years ago

The sum of 13 and twice a number

Setler79 [48]

This would be 13+2x because if x is the number, then 2 times it would be 2x and the sum means addition so it would be 13+2x

7 0

3 years ago

How do you complete this One-Step equation?<br>5 1/2 + p = 6

dalvyx [7]

5 1/2 + p = 6

subtract 5 /12 from each side

5 1/2 - 5 1/2+ p = 6 - 5 1/2

p = 6 - 5 1/2

borrow from the 6

p = 5 2/2 - 5 1/2

p = 1/2

8 0

2 years ago

Read 2 more answers

The average value of a function f over the interval [−2,3] is −6 , and the average value of f over the interval [3,5] is 20. Wha

Xelga [282]

Answer:

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

Step-by-step explanation:

Let suppose that function $f$ is continuous and integrable in the given intervals, by integral definition of average we have that:

$\frac{1}{3-(-2)} \int\limits^{3}_{-2} {f(x)} \, dx = -6$ (1)

$\frac{1}{5-3} \int\limits^{5}_{3} {f(x)} \, dx = 20$ (2)

By Fundamental Theorems of Calculus we expand both expressions:

$\frac{F(3)-F(-2)}{3-(-2)} = -6$

$F(3) - F(-2) = -30$ (1b)

$\frac{F(5)-F(3)}{5-3} = 20$

$F(5) - F(3) = 40$ (2b)

We obtain the average value of $f$ over the interval $[-2, 5]$ by algebraic handling:

$F(5) - F(3) +[F(3)-F(-2)] = 40 + (-30)$

$F(5) - F(-2) = 10$

$\frac{F(5)-F(-2)}{5-(-2)} = \frac{10}{5-(-2)}$

$\bar f = \frac{10}{7}$

The average value of $f$ over the interval $[-2,5]$ is $\frac{10}{7}$ .

4 0

2 years ago