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KiRa [710]
3 years ago
6

Oliver was counting his spare change. He had ten dimes and two quarter. How many times as many dimes does Oliver have than quart

ers
Mathematics
2 answers:
zalisa [80]3 years ago
7 0
1 quarter = 25 cents (he has 2 therefore its 50 cents)
10 dimes = 100 cents = 1 dollar
Oliver has twice as many dimes than he does quarters because 100 divided by 50 = 2. Hope this helps!
Marysya12 [62]3 years ago
4 0

Answer:

2 times as many dimes as quarter.

Step-by-step explanation:

Oliver was counting his spare change. He had 10 dimes and 2 quarters.

∵ 1 dime = $0.10

∴ 10 dimes = 10 × 0.10 = $1.00

∵ 1 quarter = $0.25

∴ 2 quarter = 2 × 0.25 = $0.50

To calculate how many times as many dimes does Oliver have than quarters we will divide dimes by quarter.

= \frac{1.00}{0.50}

= 2 times

Oliver has 2 times as many dimes as quarters.

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slega [8]

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The figure of a rhombus.

To find:

The value of x.

Solution:

We know that, if two lines intersect each other, then the vertically opposite angles are equal.

From the given figure it is clear that the diagonals intersect each other and construct two pairs of vertically opposite angles.

Since 95^\circ and x^\circ are vertically opposite angles, therefore

x^\circ=95^\circ

Hence, the value of x is 95°.

3 0
3 years ago
Tamira invests $5,000 in an account that pays 4% annual interest. How much will there be in the account after 3 years if the int
Talja [164]

Answer:

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

Step-by-step explanation:

Tamira invests $5,000 in an account

Rate of interest = 4%

Time = 3 years

Case 1:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 1

Formula :A=P(1+r)^t

A=5000(1+0.04)^3

A=5624.32

There will be $5624.32 in the account after 3 years if the interest is compounded annually.

Case 2:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 2

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{2})^{2 \times 3}

A=5630.812

There will be $5630.812 in the account after 3 years if the interest is compounded semi-annually.

Case 3:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula : A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{4})^{4 \times 3}

A=5634.125

There will be $5634.125 in the account after 3 years if the interest is compounded quarterly.

Case 4:

Principal = 5000

Rate of interest = 4%

Time = 3 years

No. of compounds per year = 4

Formula :A=P(1+\frac{r}{n})^{nt}

A=5000(1+\frac{0.04}{12})^{12 \times 3}

A=5636.359

There will be $5636.359 in the account after 3 years if the interest is compounded monthly

8 0
3 years ago
Solving Equations with the variable on each side
Maslowich
Multiply both sides by 6
(b-4)/6*6= b-4
b/2*6= 3b

Rewrite the equation
b-4= 3b

Subtract b from both sides
-4=2b

Divide both sides by 2
-2=b

Final answer: b=-2
5 0
3 years ago
Solve for x: 2 over 3 (x − 4) = 2x.
Lady bird [3.3K]

Answer:

X would equal -2. I hope this helps!

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2 years ago
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Arturiano [62]
Hey how are you doing today?
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2 years ago
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