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3 years ago

Bro its everything but A is the only wrong answer

Mathematics

2 answers:

Neko [114]3 years ago

8 0

The answers are B,C and D

astraxan [27]3 years ago

5 0

....I am not sure if this is an answerable question XD

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Please with me with translating words into equations

Blizzard [7]

2x - 27=56
the answer to the question

5 0

3 years ago

Rate and Ratios IF 3 kg of potatoes cost R24. How much will 7 kg of potatoes cost

balu736 [363]

Answer:

7kg of potatoes cost 56 R (dollars)

Step-by-step explanation:

First, we have to find the unit price of 1kg of potatoes. To do this we divide 24 by 3. That's 8. Each kg of potato costs 8 dollars.

Now, all we have to do is multiply 8 by 7.

8 is the unit rate/kg and 7kg is the amount they are asking.

8x7=56

7kg of potatoes cost 56R

4 0

2 years ago

Read 2 more answers

What is the area of a triangle with vertices (1,0) (5,0) (3,4)

Aleksandr-060686 [28]

Answer:

The area of the triangle is of 8 units of area.

Step-by-step explanation:

Answer:

The area of the triangle is of 21 units of area.

Step-by-step explanation:

The area of a triangle with three vertices $(x_1,y_1),(x_2,y_2),(x_3,y_3)$ is given by the determinant of the following matrix:

$A = \pm 0.5 \left|\begin{array}{ccc}x_1&y_1&1\\x_2&y_2&1\\1_3&y_3&1\end{array}\right|$

In this question:

Vertices (1,0) (5,0) (3,4). So

$A = \pm 0.5 \left|\begin{array}{ccc}1&0&1\\5&0&1\\3&4&1\end{array}\right|$

$A = \pm 0.5(1*0*1+0*1*3+1*5*4-1*0*3-0*5*1-1*1*4)$

$A = \pm 0.5*(20-4)$

$A = \pm 0.5*16 = 8$

The area of the triangle is of 8 units of area.

3 0

3 years ago

Jeff left 4/5 of the pumpkin pie in the refrigerator on Saturday he ate 1/2 if what was left of the pie what fraction of the ent

sukhopar [10]

He ate 2/5 of the pie on Saturday.

7 0

3 years ago

How much of a radioactive kind of thorium will be left after 14,680 years if you start with

babymother [125]

Answer:

8978 grams

Step-by-step explanation:

The equation to find the half-life is:

$N(t)= N_{0}e^{-kt}$

N(t) = amount after the time t

$N_{0}$ = initial amount of substance

t = time

It is known that after a half-life there will be twice less of a substance than what it intially was. So, we can get a simplified equation that looks like this, in terms of half-lives.

$N(t)= N_{0}e^{-\frac{ln(\frac{1}{2}) }{t_{h} } t}$ or more simply $N(t)= N_{0}(\frac{1}{2})^{\frac{1}{t_{h} } }$

$t_{h}$ = time of the half-life

We know that $N_{0}$ = 35,912, t = 14,680, and $t_{h}$ =7,340

Plug these into the equation:

$N(t) = 35912(\frac{1}{2})^{\frac{14680}{7340} }$

Using a calculator we get:

N(t) = 8978

Therefore, after 14,680 years 8,978 grams of thorium will be left.

Hope this helps!! Ask questions if you need!!

8 0

2 years ago