3 years ago

If a quadrilateral is a kite, then its diagonals are perpendicular. TRUE FALSE

Mathematics

1 answer:

Greeley [361]3 years ago

7 0

<span>If a quadrilateral is a kite, then its diagonals are perpendicular. it is true</span>

You might be interested in

If you only have the original price ($24.50) and the discount is 18% how do you find the sale price?

liberstina [14]

24.5 x (1-18%)
=$20.09

4 0

3 years ago

Solve for x. (x+6)(-x+1)=0

ValentinkaMS [17]

Answer:

x=6,1

I hope it helps :)

5 0

3 years ago

Samantha's age is 3 years more than half her uncle's age. If her uncle's age is z years, which of the following expressions best

melisa1 [442]

Answer:

See below

Step-by-step explanation:

z = uncle's age

1/2z +3 = Sam's age

4 0

2 years ago

A force of 12 lb is required to hold a spring stretched 8 in. beyond its natural length. How much work W is done in stretching i

sattari [20]

Answer:

Work done in stretching the spring = 7.56 lb-ft.

Step-by-step explanation:

Normal length of the spring = 8 in or $\frac{8}{12}$ ft

= $\frac{2}{3}$ ft

If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in

= $\frac{11}{12}$ ft

Force applied to stretch the spring = 12 lb

By Hook's law,

F = kx [where k is the spring constant and x = length by which the spring is stretched]

12 = k( $\frac{2}{3}$ )

k = 18

Work done (W) to stretch the spring by $\frac{11}{12}$ ft will be

W = $\int\limits^\frac{11}{12} _0 {kx} \, dx$

= $\int\limits^\frac{11}{12} _0 {(18x)} \, dx$

= $18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0$

= 9( $\frac{11}{12}$ )²

= 7.56 lb-ft

6 0

3 years ago

Which of the following is the definition of term?

vesna_86 [32]

What are the options it gives you?

8 0

3 years ago