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viva [34]
3 years ago
6

You are in charge of the city carnvial committee. You have $8,096.35 to spend. You have already purchased: Decorations $894.60.

Tent rental
$1.009.99, new popcorn and cotton candy machines $658.50
How much money do you have left to spend to rent carnival rides for the kids?
Mathematics
1 answer:
telo118 [61]3 years ago
5 0

Step-by-step explanation:

Total amount to spend = 8096.35

Amount already spent = 894. 60 + 1009.99 + 658.50 = 2563.09

Amount left to spend = 5533.26

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The larger of two numbers is 10 less than 5 times the smaller.their sum is 146 .find the smaller number
ExtremeBDS [4]
For this problem, you would have to use a system of equations. Hope this helps!

5 0
3 years ago
A right triangle has one angle that measure 23o. The adjacent leg measures 27.6 cm and the hypotenuse measures 30 cm.
MrMuchimi

Answer:

161.8cm²

Step-by-step explanation:

solve for height which is the opposite

opp=x

sin(theata)= opp./hyp.

sin23=x/30

x=30×sin23

x=11.72cm

height=opposite

height=11.72cm

base=adjacent

base=27.6cm

½of 27.6cm=13.8

13.8cm×11.72cm=161.74 (2d.p)

161.74 rounded to the nearest tenths= 161.7

I'm not sure if it's the answer but it's the closest thing to the options

4 0
3 years ago
In circle A as shown below, segment DC is tangent to circle A at D.
Likurg_2 [28]

Answer:

AB = 3

Step-by-step explanation:

AB = AD

AB² + 4² = (AB + 2)²

AB² + 16 = AB² + 4AB + 4

combine like terms:

4AB = 12

AB = 3

4 0
2 years ago
Read 2 more answers
HELP! Find the value of sin 0 if tan 0 = 4; 180 < 0< 270
BabaBlast [244]

Hi there! Use the following identities below to help with your problem.

\large \boxed{sin \theta = tan \theta cos \theta} \\  \large \boxed{tan^{2}  \theta + 1 =  {sec}^{2} \theta}

What we know is our tangent value. We are going to use the tan²θ+1 = sec²θ to find the value of cosθ. Substitute tanθ = 4 in the second identity.

\large{ {4}^{2}  + 1 =  {sec}^{2} \theta } \\  \large{16 + 1 =  {sec}^{2} \theta } \\  \large{ {sec}^{2}  \theta = 17}

As we know, sec²θ = 1/cos²θ.

\large \boxed{sec \theta =   \frac{1}{cos \theta} } \\  \large \boxed{ {sec}^{2}  \theta =  \frac{1}{ {cos}^{2}  \theta} }

And thus,

\large{  {cos}^{2}  \theta =  \frac{1}{17}}   \\ \large{cos \theta =  \frac{ \sqrt{1} }{ \sqrt{17} } } \\  \large{cos \theta =  \frac{1}{ \sqrt{17} }  \longrightarrow  \frac{ \sqrt{17} }{17} }

Since the given domain is 180° < θ < 360°. Thus, the cosθ < 0.

\large{cos \theta =   \cancel\frac{ \sqrt{17} }{17} \longrightarrow cos \theta =  -  \frac{ \sqrt{17} }{17}}

Then use the Identity of sinθ = tanθcosθ to find the sinθ.

\large{sin \theta = 4 \times ( -  \frac{ \sqrt{17} }{17}) } \\  \large{sin \theta =  -  \frac{4 \sqrt{17} }{17} }

Answer

  • sinθ = -4sqrt(17)/17 or A choice.
4 0
3 years ago
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