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BaLLatris [955]
3 years ago
10

I need help!! asap please

Mathematics
1 answer:
True [87]3 years ago
6 0
Is there any more information?

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How do I use substitution to solve a system of linear equations?
Pachacha [2.7K]

Answer:

the substitution method is one way to solve linear equation. the substitution method is when substitute the one y value with the other:

example :

x+y=10

y=10-x ( value of y)

2x+y=12 ( substitute the value of y in the equation )

2x+(10-x)=12

2x+10-x=12 ( now solve for x)

x=12-10

x=2 ( substitute the value of x in the equation x+y=10)

x+y=10

2+y=10

y=10-2

y=8

( i hope it helps)

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3 years ago
Solve for j<br> 9j=19+8j
charle [14.2K]

Answer: The answer would be j=19

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3 years ago
Read 2 more answers
How do I solve this
sdas [7]
\bf \textit{difference of squares}&#10;\\ \quad \\&#10;(a-b)(a+b) = a^2-b^2\qquad \qquad &#10;a^2-b^2 = (a-b)(a+b)\\\\&#10;-------------------------------\\\\&#10;\cfrac{2x}{x^2+2x-24}-\cfrac{x}{x^2-36}\quad &#10;\begin{cases}&#10;x^2+2x-24\implies (x+6)(x-4)\\&#10;--------------\\&#10;x^2-36\implies x^2-6^2\\&#10;(x-6)(x+6)&#10;\end{cases}

\bf \cfrac{2x}{(x+6)(x-4)}-\cfrac{x}{(x-6)(x+6)}\impliedby &#10;\begin{array}{llll}&#10;\textit{thus our LCD is}\\&#10;(x-6)(x+6)(x-4)&#10;\end{array}&#10;\\\\\\&#10;\cfrac{[(x-6)2x]~-~[(x-4)x]}{(x-6)(x+6)(x-4)}\implies \cfrac{2x^2-12x-x^2+4x}{(x-6)(x+6)(x-4)}&#10;\\\\\\&#10;\cfrac{x^2-8x}{(x-6)(x+6)(x-4)}
3 0
3 years ago
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