Question

Find dy, dx if f(x) = (x + 8)3x. 3xln(x + 8) the product of the quantity 3 times the natural log of the quantity x plus 8 plus 3 times x divided by the quantity x plus 8, and the quantity x plus 8 raised to the 3x power 3 times the natural log of the quantity x plus 8 plus 3 times x divided by the quantity x plus 8 3x(x + 8)(3x − 1)

Answer 1

F(x) = 9x^2(x + 8)^2

Answer 2

Answer:

$\frac{dy}{dx}=\frac{3}{x+8}$

Step-by-step explanation:

Given : The function is $f(x)=3 \ln(x+8)$

To find : The value of $\frac{dy}{dx}$ ?

Solution :

Let the function be $y=3 \ln(x+8)$

Derivate w.r.t 'x',

$\frac{dy}{dx}=\frac{d}{dx}(3 \ln(x+8))$

$\frac{dy}{dx}=3\times\frac{1}{x+8}\times 1$

$\frac{dy}{dx}=\frac{3}{x+8}$

Therefore, the value is $\frac{dy}{dx}=\frac{3}{x+8}$.