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Taya2010 [7]
3 years ago
9

Find dy, dx if f(x) = (x + 8)3x. 3xln(x + 8) the product of the quantity 3 times the natural log of the quantity x plus 8 plus 3

times x divided by the quantity x plus 8, and the quantity x plus 8 raised to the 3x power 3 times the natural log of the quantity x plus 8 plus 3 times x divided by the quantity x plus 8 3x(x + 8)(3x − 1)
Mathematics
2 answers:
boyakko [2]3 years ago
8 0
F(x) = 9x^2(x + 8)^2
guajiro [1.7K]3 years ago
6 0

Answer:

\frac{dy}{dx}=\frac{3}{x+8}

Step-by-step explanation:

Given : The function is f(x)=3 \ln(x+8)

To find : The value of \frac{dy}{dx} ?

Solution :

Let the function be y=3 \ln(x+8)

Derivate w.r.t 'x',

\frac{dy}{dx}=\frac{d}{dx}(3 \ln(x+8))

\frac{dy}{dx}=3\times\frac{1}{x+8}\times 1

\frac{dy}{dx}=\frac{3}{x+8}

Therefore, the value is \frac{dy}{dx}=\frac{3}{x+8}.

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