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Vladimir79 [104]
3 years ago
7

Solve the following system of equations for x 2x-y=4 y-x=4

Mathematics
2 answers:
Dominik [7]3 years ago
6 0

Answer:

x = 8

y = 12

Step-by-step explanation:

Given equations are -

2x - y = 4         .......(1)

-x + y = 4         ........(2)

Add both equations, we get

2x - y + (-x + y) = 4 + 4

⇒2x - y - x + y = 8

⇒x = 8

Now,

Put the value of x in equation (2), we get

y - 8 = 4

⇒y = 4 + 8

⇒y = 12

∴ we get

x = 8

y = 12

Yuliya22 [10]3 years ago
4 0

Answer:

What do i do???

Step-by-step explanation:

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On the right side, give a reason to justify each step made on the left
cestrela7 [59]

Given that: step 1

3x+12=8x-18

step 2: subtract 3x both side

\begin{gathered} 3x+12-3x=8x-3x-18 \\ 12=5x-18 \end{gathered}

Step 3: Add 18 both side:

\begin{gathered} 12+18=5x-18+18 \\ 30=5x \end{gathered}

Step 4: divide both side by 5

\begin{gathered} \frac{30}{5}=\frac{5x}{5} \\ 6=x \end{gathered}

Step:6 The value of x is:

x=6

8 0
1 year ago
Find all critical points of the given plane autonomous system. (Enter your answers as a comma-separated list.) x′ = x 12 − x − 1
Andru [333]

Answer:

the critical points are (0,0) , (0, 20), (12, 0) , (4,16)

Step-by-step explanation:

To consider the autonomous system

x' =x (12 -x - \dfrac{1}{2})

y' = y( 20 -y - x)

The critical points of the above system can be derived by replacing x' = o and y' = 0.

i.e.

x' =x (12 -x - \dfrac{y}{2}) = 0

\dfrac{x}{2} (24 -2x - y) = 0

x = 0 or 24 - 2x - y = 0     ----- (1)

Also

y' = y( 20-y-x) = 0

y( 20 -y - x) = 0

y = 0 or 20 - y - x = 0  -----   (2)

By solving (1) and (2);

we get x = 4 and y = 16

Suppose x = 0 from (2)

y = 20

Also;

if y = 0 from (1)

x = 12

Thus, the critical points are (0,0) , (0, 20), (12, 0) , (4,16)

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Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Question 6: please help me out here :(((
Murljashka [212]

Answer:

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Step-by-step explanation:

Given: m∠5 = 106

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The Alternate Interior Angles Theorem states that, when two parallel lines are cut by a transversal , the resulting alternate interior angles are congruent.

Therefore: m∠1 = 106

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