Answer:

Step-by-step explanation:
Given:
x>0
Which means
x is any number greater than 0 ig 1,2,3,4,5,7,9.......
y<0
Which means
y Is any number smaller than 0
ig -1,-2,-3,-4,-5.........
So according to the question
The coordinates are
(x,-y)
Therefore,
The points are located to Quadrant IV
Answer:

Step-by-step explanation:

Make both a single fraction by adding together.



Simplify


Answer:
The surface area of the right regular hexagonal pyramid is 50.78 cm².
Step-by-step explanation:
Given:
A right regular hexagonal pyramid with sides(s) 2 cm and slant height(h) 5 cm.
Now, to find the surface area(SA) of the right regular hexagonal pyramid.
So, we find the area of the base(b) first:
Area of the base = ![\sqrt[3]{3}\times s^{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D%5Ctimes%20s%5E%7B2%7D)
= ![\sqrt[3]{3}\times 2^{2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B3%7D%5Ctimes%202%5E%7B2%7D)
On solving we get:
Area of the base(b) = 
Then, we find the perimeter(p) :
Perimeter = s × 6

Now, putting the formula for getting the surface area:
Surface area = perimeter × height/2 + Area of the base.




As, <em>the surface area is 50.784 and rounding to nearest hundredth becomes 50.78 because in hundredth place it is 8 and in thousandth place it is 4 so rounding to it become 50.78.</em>
Therefore, the surface area of the right regular hexagonal pyramid is 50.78 cm².
<h3>
Answer: c. 8(y-6) = (x-2)^2</h3>
Explanation:
The directrix is horizontal, so the axis of symmetry is vertical. We'll have an x^2 term. The vertical distance from y = 4 to y = 8 is 4 units. Cut this in half to get 2, which is the focal distance p = 2.
The point (2,4) is directly below (2,8), and the point is on the directrix. The midpoint between (2,4) and (2,8) is (2,6). This is the vertex.
(h,k) = (2,6)
4p(y-k) = (x-h)^2
4*2(y-6) = (x-2)^2
8(y-6) = (x-2)^2
Answer:
3rfwf
Step-by-step explanation:
a,c e