Answer:
1.2833333333....
Step-by-step explanation:
Just add it
ANSWER

EXPLANATION
Part a)
Eliminating the parameter:
The parametric equation is


From the first equation we make t the subject to get;


We put it into the second equation.


We differentiate to get;

At x=5,


The slope of the tangent is 2.
The equation of the tangent through
(5,6) is given by




Without eliminating the parameter,



At x=5,



This implies that,

The slope of the tangent is 2.
The equation of the tangent through
(5,6) is given by



No, this would not be a linear function. Being linear means it creates a straight line, but this function has an x squared. Anytime x^2 is in a function, the graph is a u shape, called a parabola. A simple linear function is y=x :D
If you were to use the substitution method to solve the following system, we need to write one of the equation to an <span>expression equivalent to y. Let us say the second equation, we write it as follows:
</span><span>6x – 3y = –3
-3y = -6x - 3
y = 2x + 1
We substitute the equation to the first given equation as follows:
</span><span>2x – 5y = –3
</span>2x – 5(2x + 1) = –3
2x - 10x - 5 = -3
-8x = 2
x = -1/4
y = 2(-1/4) + 1 = 1/2
Okay! 4/16= 0.25 because 16/16 = 1 and so that means 12/16 = 0.75 and 8/16 = 0.50 and 4/16 = 0.25 Hope this helped!