Answer:
a) X ~ 
b) μ = 100/3
c) 
d) A battery is expected to last 100/3 months (33 months and 10 days approximately).
e) For seven batteries, i would expect them to last 700/3 months (approximately 19 years, 5 months and 10 days).
Step-by-step explanation:
a) The life of a battery is usually modeled with an exponential distribution X ~ 
b) The mean of X is μ = 1/0.03 = 100/3
c) The standard deviation is 
d) The expected value of the bateery life is equal to its mean, hence it is 100/3 months.
e) The expected value of 7 (independent) batteries is the sum of the expected values of each one, hence it is 7*100/3 = 700/3 months.
Answer:
12
Step-by-step explanation:
Hope this helps
Answer:
4x^2+17x+15
Step-by-step explanation:
(4x-3)(x+5)
= 4x(x+5) -3(x+5)
= 4x^2+ 20x -3x + 15
= 4x^2 + 17x + 15
The approximation to estimate will be 0.2498
The mistake is n third line - adding 3w
96 + 2w =2(80 - 3w)
96 + 2w = 160 - 6w
+ 6w + 6w
96 + 8w = 160
- 96 -96
8w = 64
w = 8 weeks answer