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Anna [14]
3 years ago
14

What is 18 + 348 + 46 + 924

Mathematics
1 answer:
Rina8888 [55]3 years ago
8 0
1336 is your answer.

Hope this helped :)
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Anyone that can help me with this?
Flauer [41]
Okay. 10×5=50cm^2 is the area of the rectangle
The height of the triangle is (18-10)=8cm
So (8×5)÷2=20cm^2
50+20=70cm^2 is the area of the composite shape
8 0
3 years ago
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Which line is a slop that is positive
dexar [7]

Answer: A

Step-by-step explanation:

4 0
3 years ago
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Name the lengths of the sides of three rectangles with perimeters of 12 units. use only whole numbers
disa [49]


3x4=12      1x12=12       6x2=12   

You just need to be able to multiply the sides to equal 12. I hope that helps. :)

4 0
3 years ago
Pretty Pavers company is installing a driveway. Below is a diagram of the driveway they are
prohojiy [21]

Answer:

The most correct option is;

(B) 958.2 ft.²

Step-by-step explanation:

From the question, the dimension of each square = 3 ft.²

Therefore, the length of the sides of the square = √3 ft.

Based on the above dimensions, the dimension of the small semicircle is found by counting the number of square sides ti subtends as follows;

The dimension of the diameter of the small semicircle = 10·√3

Radius of the small semicircle = Diameter/2 = 10·√3/2 = 5·√3

Area of the small semicircle = (π·r²)/2 = (π×(5·√3)²)/2 = 117.81 ft.²

Similarly;

The dimension of the diameter of the large semicircle = 10·√3 + 2 × 6 × √3

∴ The dimension of the diameter of the large semicircle = 22·√3

Radius of the large semicircle = Diameter/2 = 22·√3/2 = 11·√3

Area of the large semicircle = (π·r²)/2 = (π×(11·√3)²)/2 = 570.2 ft.²

Area of rectangle = 11·√3 × 17·√3 = 561

Area, A of large semicircle cutting into the rectangle is found as follows;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (\theta - sin\theta) \times r^2

Where:

\theta = 2\times tan^{-1}( \frac{The \, number \, of  \, vertical  \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle}{The \, number \, of  \, horizontal \, squrare  \, sides  \ cut  \,  by  \  the  \  large  \,  semicircle} )

\therefore \theta = 2\times tan^{-1}( \frac{10\cdot \sqrt{3} }{5\cdot \sqrt{3}} ) = 2.214

Hence;

A_{(segment \, of \, semicircle)} = \frac{1}{4} \times (2.214 - sin2.214) \times (11\cdot\sqrt{3} )^2 = 128.3 \, ft^2

Therefore; t

The area covered by the pavers = 561 - 128.3 + 570.2 - 117.81 = 885.19 ft²

Therefor, the most correct option is (B) 958.2 ft.².

4 0
2 years ago
Solve:<br> -3/4+p=1/2<br> Thank you so much!
shepuryov [24]

-3 / 4 + p = 1/2

LCD 4 and 2 = 4

Multiply by LCD = 4

p. (4)- 3/4 .( 4 ) = 1/2.(4)

4 p - 3 = 2

Add 3 to both sides:

4 p - 3 + 3 = 2 + 3

4 p = 5

Divide both sides by 4 :

4p / 4 =  5 /4

p = 5/4

3 0
3 years ago
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