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Misha Larkins [42]
3 years ago
12

28. Find the perimeter of the polygon. 9 mm a. 55 mm b. 54 mm c. 52 mm

Mathematics
1 answer:
UNO [17]3 years ago
6 0

Answer:

I don't see a polygon anywhere...

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How to solve this. I am very confused.
sergiy2304 [10]

To solve, we will need to plug in -5 for x in both instances.

|-5 + 2| / -5 + 2

|-3| / -3

Now, these absolute value bars may be a bit puzzling. What we have to do is take the absolute value of the number inside of the brackets. Meaning, that if the number is negative, we make it positive, and if the number is positive, then it stays positive.

3 / -3

-1

Hope this helps!! :)

6 0
3 years ago
Read 2 more answers
WILL MARK BR HELP ME PLZ FAST AS POSSIBLE
posledela
<h2>Answer:</h2>

<h2>cos theta= adjacent side/ hypotenuse</h2><h2 /><h2>cos theta= adjacent side/ hypotenusecos 36= x/8</h2><h2 /><h2>cos theta= adjacent side/ hypotenusecos 36= x/8√5+1/4 = x/8</h2><h2 /><h2>cos theta= adjacent side/ hypotenuse </h2>

cos 36= x/8√5+1/4 = x/8

4.7 is the approximate answer

8 0
3 years ago
How can 32x6 be distributed
Black_prince [1.1K]
(30x6)+(2x6) would get you the same answer as 32x6
6 0
3 years ago
For questions 1-3 select which relation is a function.
Akimi4 [234]

Answer:

There is no picture

Step-by-step explanation:

7 0
3 years ago
Sara's teacher has 6 7/8 cups of water. She used 4/8 a cup of water to water the plant on her desk and 3 2/8 cups for some stude
PIT_PIT [208]

Answer:

Amount of water left = 25 / 8 cups

Step-by-step explanation:

Given:

Amount of water teacher Sara have = 6\frac{7}{8} cups = 55 / 8 cups

Amount of water teacher used = 4/8 cups

Amount of water used by student = 3\frac{2}{8} cups = 26 / 8 cups

Find:

Amount of water left

Computation:

Amount of water left = Amount of water teacher Sara have - [Amount of water teacher used + Amount of water used by student]

Amount of water left = [55/8] - [4/8 + 26/8]

Amount of water left = [55/8] - [30/8]

Amount of water left = [55-30] / 8

Amount of water left = 25 / 8 cups

5 0
3 years ago
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