Answer:
The correct answer is
0.5 F, 0.5 f
Step-by-step explanation:
We note the following
Number of colored circles in the box = 14
Number of red circles in the box = 4
Number of purple circles in the box = 6
Number of blue circles in the box = 4
The allele frequency are as follows
Where the frequency is given as
Genotype Frequency Relative frequency
FF = Red 4 4/14 (0.29≈0.3)
Ff = Purple 6 6/14 (0.43≈0.4)
ff = Blue 4 4/14(0.29≈0.3)
Within this population,
We however have 4 FF = 8 F
6 Ff = 6 F + 6 f and
4 ff = 8 f
Total allele = 8+6+6+8 = 28
Relative frequency of F = (8+6)/28 = 14/28 = 0.5
relative frequency of f = (8+6)/28 = 0.5
Therefore the allele frequencies in the palm tree population is
0.5 F, 0.5 f
When in equilibrium we have
However the FF has the product of F×F which is = F² = 0.29 so the frequency of F = √(0.29) = 0.535≈ 0.5
The frequency of Ff is Ff or fF = 0.43 since there is equal number of each allele in Ff we have fF or Ff = Ff = 0.43
Which hives 0.43/2 = F =f ≈ 0.2
To
and ff = 0.29 so that f = 0.535 ≈ 0.5
Therefore f = F = 0.5 + 0.2 = 0.7
and 
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