Answer:
c
Step-by-step explanation:
Answer:
A) (1 s, 2.3 s)
B) (-4 m/s², 3.8 m/s²)
Step-by-step explanation:
The car's position which is the distance is given by the equation;
s(t) = t³ - 5t² + 7t
A) Velocity is the first derivative of the distance. Thus;
v(t) = ds/dt = 3t² - 10t + 7
At v = 0, we have;
3t² - 10t + 7 = 0
Using quadratic formula, we have;
t = 1 and t = 2.3
Thus, time at velocity of 0 is t = (1 s, 2.3 s)
B) acceleration is the derivative of the velocity. Thus;
a(t) = dV/dt = 6t - 10
At velocity of 0, we got t = 1 and t = 2.3
Thus;
a(1) = 6(1) - 10 = -4 m/s²
a(2.3) = 6(2.3) - 10 = 3.8 m/s
Thus, a(t) at v = 0 gives; (-4 m/s², 3.8 m/s²)
Answer:
<h2>|1.7| = 1.7</h2>
Step-by-step explanation:
Definition of absolute value:
|a| = a if a ≥ 0
|a| = -a if a < 0
Examples:
|2| = 2
|-2| = -(-2) = 2
|0.45| = 0.45
|-0.45| = -(-0.45) = 0.45
|1000| = 1000
|-1000| = 1000
Therefore
|1.7| = 1.7
The answer is UAGCGUGCA I think
