Which ordered pair in the form (a, b) is a solution of this equation?
2 answers:
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Answer:
Step-by-step explanation:
The question above is answered below.
Take the LCM of the denominators and simplify. The LCM is 12.
To get 6 + 2 above, we divide 12 by 4 which equals 3 then multiply 3 by 2, total 6. Similarly to get 2, we say 13 divided by 2, equals 2; 2 times 1 equals 2.
The fraction above has to be simplified to reduced form. Thus the answer below.
Therefore, the total amount of walnuts and pecans needed for the recipe is 2/3.
9514 1404 393
Answer:
- maximum: (x, y) = (12.4n+3.2, 186.322)
- minimum: (x, y) = (12.4n+9.4, 163.498)
Step-by-step explanation:
You know that cos(α) is a maximum at α=0, 2π, 4π, and all even multiples of π. You know cos(α) is a minimum for α=π, 3π, 5π, and all odd multiples of π.
You can find your value of x at which y will be a maximum by setting the argument of the cosine function equal to zero (and/or 2nπ). If we use α=2nπ, then we have ...
α = (5π/31)(x -3.2) = 2nπ
(x -3.2) = (31/5)(2n) = 12.4n
Tidal maxima will occur at ...
x = 12.4n +3.2 . . . . . for integer values of n
Without bothering to go through the solution for α being odd multiples of π, we can see from this that the period is 12.4 hours. We know the tidal minimum will be half a period later, or 6.2 hours later than this.
Tidal minima will occur at ...
x = 12.4n +9.4 . . . . for integers n
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Of course, cos(α) has extremes of ±1, so your tidal maximum will be ...
y = 11.412 +174.91 = 186.322
and your tidal minimum will be ...
y = -11.412 +174.91 = 163.498
