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Tresset [83]
3 years ago
13

Answer Please :( I need help:(

Mathematics
2 answers:
snow_tiger [21]3 years ago
4 0
I would write 300 divided by t because she has 300 chairs and needs to divide them among “t” tables.
I hope this helped! :-)
pogonyaev3 years ago
3 0
T/300
Or 300 divided by t
Both mean the same
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What is the volume of a sphere with a diameter of 43.5 cm, rounded to the nearest tenth of a cubic centimeter?
Akimi4 [234]

Answer

= 43098.92

Step-by-step explanation:

Good luck

i solved and got that

7 0
4 years ago
What is the answer???
Mama L [17]

Remark

There must be 12 such boxes. Each one has a volume of 4 * 4 * 4 = 64 in^3

Proportion

1 box is 64 in^3

12 boxes = x

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x = 768 in^3

Note: We are not concerned with how to stack these boxes. We only want to know the volume.

6 0
3 years ago
Drag the operations into the order in which they should be performed to evaluate the expression below. 7 × 6 ÷ ( 13 − 10 ) + 4 a
monitta

Answer:It's 18

Step-by-step explanation:Multiply 7 and 6 to get 42

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5 0
3 years ago
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Can someone explain this to me since I don’t get it that well?
Tatiana [17]

so it'd be the first, third and fourth one. all you gotta do is draw a vertical line through the middle of the 1st, 3rd and 4th.

4 0
3 years ago
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 270 day
dusya [7]

Answer:

a) 281 days.

b) 255 days

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 270, \sigma = 8

​(a) What is the minimum pregnancy length that can be in the top 8​% of pregnancy​ lengths?

100 - 8 = 92th percentile.

X when Z has a pvalue of 0.92. So X when Z = 1.405.

Z = \frac{X - \mu}{\sigma}

1.405 = \frac{X - 270}{8}

X - 270 = 1.405*8

X = 281

(b) What is the maximum pregnancy length that can be in the bottom 3​% of pregnancy​ lengths?

3rd percentile.

X when Z has a pvalue of 0.03. So X when Z = -1.88

Z = \frac{X - \mu}{\sigma}

-1.88 = \frac{X - 270}{8}

X - 270 = -1.88*8

X = 255

8 0
4 years ago
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