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3 years ago

matt ran 8 laps in 1,256 seconds if he ran each lap in the same amount of time how many seconds did it take him to run 1 lap

Mathematics

1 answer:

Murrr4er [49]3 years ago

4 0

Answer:

you need to divide 1,256 by 8 which, is 157 seconds

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Given: ∆ABC –iso. ∆, m∠BAC = 120°

lidiya [134]

Answer: $P\triangle ADH = (a+b+\sqrt{a^2+b^2} )$ unit

Step-by-step explanation:

Since Here Δ ABC is a isosceles triangle.

Also, $AH\perp BC$ and $HD\perp AC$

Thus, ∠ ADH = 90°

That is, Δ ADH is the right angle triangle.

In which, AD = a unit and HD = b unit

And, By the definition of Pythagoras theorem,

$AH^2 = HD^2 + AD^2$

⇒ $AH^2 = a^2 +b^2$

⇒ $AH = \sqrt{a^2+b^2}$

Since, the perimeter of a triangle = sum of the all sides of the triangle.

Therefore, perimeter of ΔADH = AD + DH + AH

= $a + b + \sqrt{a^2+b^2}$ unit

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2 years ago

Natalie is making a scrapbook. She has 12 stickers and she still needs to make 4 more pages. She wants each page to have the sam

nydimaria [60]

Answer:

Step-by-step explanation:

The true answer is 12 divided by four bu the closest I can see is the last one

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2 years ago

Find the sum: 4+(-11)

Elden [556K]

Answer:

-7

Step-by-step explanation:

4 + (-11)

=> {since, positive x negative = negative}

=> 4 - 11

=> -7

3 0

1 year ago

Read 2 more answers

Which equation does not have the same solution as the others?

kkurt [141]

X+12=20 is 8.

x-9=17 and 2x=16 both have the same solution.

The answer should be X+12=20.

5 0

3 years ago

Read 2 more answers

HELP PELASE ILL MARK BRAINLIEST AND POINTS!

UNO [17]

$\qquad\qquad\huge\underline{{\sf Answer}}$

Both the given lines in graph intersect at point (5 , -2), the point must satisfy both the equations.

and if we check the options, we will observe that D. option has both the equations that satisfy the given conditions.

that is ~

$\qquad \sf \dashrightarrow \: x + y = 3$

put y = - 2,we will get :

$\qquad \sf \dashrightarrow \: x - 2 = 3$

$\qquad \sf \dashrightarrow \: x = 5$

so, 1st equation satifys the condition. let's check out 2nd one.

$\qquad \sf \dashrightarrow \: x + 2y = 1$

put y = -2

$\qquad \sf \dashrightarrow \: x + (2 \times - 2) = 1$

$\qquad \sf \dashrightarrow \: x - 4 = 1$

$\qquad \sf \dashrightarrow \: x = 5$

Hence, we can conclude that the Correct choice is D

5 0

2 years ago