1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
likoan [24]
3 years ago
7

How much lashonda paid ?

Mathematics
1 answer:
Nonamiya [84]3 years ago
7 0

61 - (61 x .85) = 9.15

You might be interested in
Given the information in the picture, which trigonometric identity can be used to solve for the height of the blue ladder that i
Stells [14]

The trigonometric identity can be used to solve for the height of the blue ladder that is leaning against the building is \rm sin=\dfrac{o}{h}.

We have to determine

Which trigonometric identity can be used to solve for the height of the blue ladder that is leaning against the building?.

<h3>Trigonometric identity</h3>

Trigonometric Identities are the equalities that involve trigonometry functions and hold true for all the values of variables given in the equation.

Trig ratios help us calculate side lengths and interior angles of right triangles:

The trigonometric identity that can be used to solve for the height of the blue ladder is;

\rm Sin47=\dfrac{50}{H}\\\\H=\dfrac{50}{sin47}\\\\H=68 feet

Hence, the trigonometric identity can be used to solve for the height of the blue ladder that is leaning against the building is \rm sin=\dfrac{o}{h}.

To know more about trigonometric identity click the link given below.

brainly.com/question/1256744

6 0
2 years ago
⎧
d1i1m1o1n [39]

<u>Given</u>:

The given expression to find the nth term of the sequence is d(n)=d(n-1) \cdot (-5)

The first term of the sequence is d(1)=8

We need to determine the third term of the sequence.

<u>Second term:</u>

The second term of the sequence can be determined by substituting n = 2 in the nth term of the sequence.

Thus, we have;

d(2)=d(2-1) \cdot (-5)

d(2)=d(1) \cdot (-5)

d(2)=8 \cdot (-5)

d(2)=-40

Thus, the second term of the sequence is -40.

<u>Third term:</u>

The third term of the sequence can be determined by substituting n = 3 in the nth term of the sequence.

Thus, we have;

d(3)=d(3-1) \cdot (-5)

d(3)=-40 \cdot (-5)

d(3)=120

Thus, the third term of the sequence is 120.

7 0
3 years ago
Read 2 more answers
Find the limit
Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]

\large\underline{\sf{Solution-}}

Given expression is

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]

On substituting directly x = 1, we get,

\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}

\rm \: = \sf \: \: - \infty \: - \: \infty

which is indeterminant form.

Consider again,

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]

can be rewritten as

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]

\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}

\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}

\rm \: = \: \sf \boxed{2}

Hence,

\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}

\rule{190pt}{2pt}

7 0
2 years ago
Read 2 more answers
Help me please! If you DO decide to help, please explain it to me since I'm extremely confused! THANK YOU!
den301095 [7]

\bf \cfrac{(-4x^2)(2x^{-2}y)^3}{(16x^5)(4y^3)^2}\implies \cfrac{(-4x^2)(2^3x^{-2\cdot 3}y^3)}{(16x^5)(4^2y^{3\cdot 2})}\implies \cfrac{(-4x^2)(8x^{-6}y^3)}{(16x^5)(16y^6)} \\\\\\ \cfrac{-32x^{2-6}y^3}{256x^5y^6}\implies -\cfrac{x^{-4} y^3}{8x^5y^6}\implies -\cfrac{1}{8x^5x^{4}y^6y^{-3}}\implies -\cfrac{1}{8x^{5+4}y^{6-3}} \\\\\\ -\cfrac{1}{8x^9y^3}

8 0
3 years ago
Read 2 more answers
Which of the following statements is TRUE? a. If your original creditor (ex: credit card company) sells your debt to a collectio
nikitadnepr [17]

Answer:

the answer is d

Step-by-step explanation:

i just know its fine.

8 0
3 years ago
Read 2 more answers
Other questions:
  • Find the variable of x. <br> 8x-2=-9+7x
    11·2 answers
  • 8.25 greater than 8.250
    14·2 answers
  • Simpilify the expresssion 2+3i/4+3i
    6·1 answer
  • Sasha has 3.20 in U.S. coins. She has the same number of quarters and nickels. What is the greatest number of quarters she could
    8·2 answers
  • For this distance-time graph, what is the velocity of the car?
    12·1 answer
  • The sum of three integers is 193. The sum of the first and second integers exceeds the third by 13. The third integer is 11 less
    12·1 answer
  • Why does the vertical line test tell us whether the graph of a relation represents a function?
    7·1 answer
  • FOR 47 POINTS PLEASE HELP
    6·1 answer
  • Create 2 new equivalent fractions by multiplying the numberator and denominator of the given fractions by a non-zero number.​
    6·1 answer
  • Juan feeds his dog 2 scoops of dry dog food every day. Each scoop weighs pound. He bought a new 12-pound bag of dog food. How ma
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!