Long Piece: x + 18
Short Piece: x
(x) + (x + 18) = 84
2x + 18 = 84
2x = 66
x = 33
Long Piece: x + 18 = (33) + 18 = 51
Answer: 33 meters and 51 meters
I believe the answer would be x20. Between the two parentheses there's a multiplication symbol. So you would just pretend that the parentheses aren't there cause the variable(s) (x) is/are like terms. So you would just multiply 10 times 2 and put out the x back in front of it
Using the z-distribution, it is found that the 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 95% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.96.
The sample size and the estimate are given by:

Hence:


The 95% confidence interval for the proportion of sales that occured in December is (0.1648, 0.2948).
More can be learned about the z-distribution at brainly.com/question/25890103
Cosine = adjacent / hypotenuse
cosine = 1 / square root (2)
Answer:
Step-by-step explanation:
A larger set that a particular set can be a subset of is a Universal set. A universal set is parent where all other sets are derived from.
For example, given a universal set U = {1,2,3,4,5}, a set A = {1, 3, 5} is said to be a subset of the set U because the elements of set B are contained in the Universal set U.
Also, sets like {1, 4,5} and {3,4,5} can also be regarded as the subset of U since all the elements of the sets can be found in the Universal set U. Hence the correct name of the set is a UNIVERSAL SET