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avanturin [10]
2 years ago
11

Can anyone help pleaseeee?

Mathematics
1 answer:
ohaa [14]2 years ago
7 0
<h3>Answer:</h3>

<u>C</u><u>.</u><u> </u><u>0</u><u> </u><u>+</u><u> </u><u>4</u><u>y</u><u> </u><u>=</u><u> </u><u>2</u>

<h3>Explaination:</h3>

x + y =7 .. (1)

x - 3y = 5 ..(2)

Subtracting equation (2) from (1) , we get,

•°•4y = 2

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PLEASE ANSWER THIS ASAP I WILL MARK YOU THE BRAINLIEST
ratelena [41]

You just literally mark the graph, you see the 1st points (2,12) go on the X axis to 2, then go up to 12 and mark that as a point. and continue with this tactic with the rest.

4 0
3 years ago
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The balance, B, in dollars, after T years of an investment that earns interest compounded annually is given by the function B(t)
faust18 [17]

Answer: I’m pretty sure it’s 4.50%

Step-by-step explanation:

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2 years ago
Using properties of sets show that : a) A ∩ (A’ U B) = A ∩ B b) A ∩ (A U B )’ = Ф
asambeis [7]

Answer:

a) From A ∩ A' = ∅, we have;

A ∩ (A' ∪ B) = A ∩ B

b) From A ∩ (A' ∩ B') = (A ∩ A') ∩ B' and A ∩ A' = ∅, we have;

A ∩ (A ∪ B)' = ∅

Step-by-step explanation:

a) By distributive law of sets, we have;

A ∩ (B ∪ C) = (A ∩ B) ∪ (A ∩ C)

From the complementary law of sets, we have;

A ∩ A' = ∅

Therefore, for A ∩ (A' ∪ B) = A ∩ B, we have

A ∩ (A' ∪ B) = (A ∩ A') ∪ (A ∩ B) (distributive law of sets)

A ∩ A' = ∅ (complementary law of sets)

Therefore;

(A ∩ A') ∪ (A ∩ B) = ∅ ∪ (A ∩ B)  = (A ∩ B) (Addition to zero identity property)

∴  A ∩ (A' ∪ B) = A ∩ B

b) By De Morgan's law

(A ∪ B)' = A' ∩ B'

Therefore, A ∩ (A ∪ B)' = A ∩ (A' ∩ B')

By associative law of sets, we have;

A ∩ (A' ∩ B') = (A ∩ A') ∩ B'

A ∩ A' = ∅ (complementary law of sets)

Therefore, (A ∩ A') ∩ B' = ∅  ∩ B' = ∅

Which gives;

A ∩ (A ∪ B)' = ∅.

4 0
3 years ago
Slove for t : /3t - 6/=12​
koban [17]

Answer:

6 or -2

Step-by-step explanation:

|3t - 6| = 12

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Step-by-step explanation:

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