So if we have h(x) if multiplication isolate k-3andx-6 2x-3 = 6+7=13 value=62
Answer:
2.5 days
Step-by-step explanation:
Answer:
946.242 milliliters
Step-by-step explanation:
The client drank 6 ounces of orange juice and 4 ounces of coffee for breakfast. We need to convert ounces to milliliters
1 ounce = 29.574 milliliters
6 ounces of orange juice
= 6 × 29.574 = 177.444 milliliters
4 ounces of coffee = 4 × 29.574 = 118.296 milliliters
For lunch, he consumed 8 ounces of tea and 6 ounces of ginger ale.
8 ounces of tea = 8 × 29.574 =236.529 milliliters
6 ounces of ginger ale = 6 × 29.574 =177.444 milliliters
4 ounces of water at 10:00 a.m. and at 2:00 p.m. this means 8 ounces of water.
8 ounces of water = 8 × 29.574 =236.529 milliliters
Total consumption by the client =
177.444 + 118.296 + 236.529 + 236.529= 946.242 milliliters
Substitute

, so that

![\dfrac{\mathrm d^2y}{\mathrm dx^2}=\dfrac{\mathrm d}{\mathrm dx}\left[\dfrac1x\dfrac{\mathrm dy}{\mathrm dz}\right]=-\dfrac1{x^2}\dfrac{\mathrm dy}{\mathrm dz}+\dfrac1x\left(\dfrac1x\dfrac{\mathrm d^2y}{\mathrm dz^2}\right)=\dfrac1{x^2}\left(\dfrac{\mathrm d^2y}{\mathrm dz^2}-\dfrac{\mathrm dy}{\mathrm dz}\right)](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cmathrm%20d%5E2y%7D%7B%5Cmathrm%20dx%5E2%7D%3D%5Cdfrac%7B%5Cmathrm%20d%7D%7B%5Cmathrm%20dx%7D%5Cleft%5B%5Cdfrac1x%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dz%7D%5Cright%5D%3D-%5Cdfrac1%7Bx%5E2%7D%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dz%7D%2B%5Cdfrac1x%5Cleft%28%5Cdfrac1x%5Cdfrac%7B%5Cmathrm%20d%5E2y%7D%7B%5Cmathrm%20dz%5E2%7D%5Cright%29%3D%5Cdfrac1%7Bx%5E2%7D%5Cleft%28%5Cdfrac%7B%5Cmathrm%20d%5E2y%7D%7B%5Cmathrm%20dz%5E2%7D-%5Cdfrac%7B%5Cmathrm%20dy%7D%7B%5Cmathrm%20dz%7D%5Cright%29)
Then the ODE becomes


which has the characteristic equation

with roots at

. This means the characteristic solution for

is

and in terms of

, this is

From the given initial conditions, we find


so the particular solution to the IVP is
The center of the circle is expressed as (h,k) in the standard form of equation. In this case, the diameter endpoints are <span>(-3, 8) and (7, 4). Hence the circle center has coordinates which are the midpoints of the two points.
x = (-3 + 7) /2 = 2
y = (8 + 4) /2 = 6
hence the center of the circle is (2,6)</span>