5b^3 sq rt of a
There's not enough a's
Answer:
36.50
To two decimal places
Step-by-step explanation:
The hypothenuse side in a right angle triangle has 58cm. While the angle touching one of its leg is 51°. How long is that leg.
From the right angled triangle, the size of the leg touching the hypothenuse is the adjacent side of the triangle, hence in trigonometry, the cosine rule is used, because it involves the adjacent and the hypotenuse.
Cos 51°=x/58
Let the size of the leg be x
Making x the subject
x=58(Cos51°)
x=36.500058
Correct to two decimal place
x=36.50
Explanation:
first find the slope m of the line passing through the
the 2 given points
to calculate the slope m use the
gradient formula
∙
x
m
=
y
2
−
y
1
x
2
−
x
1
let
(
x
1
,
y
1
)
=
(
1
,
3
)
and
(
x
2
,
y
2
)
=
(
−
5
,
6
)
m
=
6
−
3
−
5
−
1
=
3
−
6
=
−
1
2
given a line with slope m then the slope of a line
perpendicular to it is
∙
x
m
perpendicular
=
−
1
m
hence
m
perpendicular
=
−
1
−
1
2
=
2
the equation of a line in
slope-intercept form
is.
∙
x
y
=
m
x
+
b
where m is the slope and b the y-intercept
here
m
=
2
y
=
2
x
+
b
←
is the partial equation
to find b substitute
(
−
2
,
7
)
into the partial equation
7
=
−
4
+
b
⇒
b
=
7
+
4
=
11
y
=
2
x
+
11
←
is the required equation
Answer:
This is a hard question I’m not sure
Step-by-step explanation:
Please provide an image for us
