Ok, I'm going to start off saying there is probably an easier way of doing this that's right in front of my face, but I can't see it so I'm going to use Heron's formula, which is A=√[s(s-a)(s-b)(s-c)] where A is the area, s is the semiperimeter (half of the perimeter), and a, b, and c are the side lengths.
Substitute the known values into the formula:
x√10=√{[(x+x+1+2x-1)/2][({x+x+1+2x-1}/2)-x][({x+x+1+2x-1}/2)-(x+1)][({x+x+1+2x-1}/2)-(2x-1)]}
Simplify:
<span>x√10=√{[4x/2][(4x/2)-x][(4x/2)-(x+1)][(4x/2)-(2x-1)]}</span>
<span>x√10=√[2x(2x-x)(2x-x-1)(2x-2x+1)]</span>
<span>x√10=√[2x(x)(x-1)(1)]</span>
<span>x√10=√[2x²(x-1)]</span>
<span>x√10=√(2x³-2x²)</span>
<span>10x²=2x³-2x²</span>
<span>2x³-12x²=0</span>
<span>2x²(x-6)=0</span>
<span>2x²=0 or x-6=0</span>
<span>x=0 or x=6</span>
<span>Therefore, x=6 (you can't have a length of 0).</span>
Step-by-step explanation:
<h3>this is given that the figure is a hexagon</h3><h3>let give a name to the given hexagon be ABCDEF</h3>
<h3>Angle a + B + C + D = 720 ( Ls sum pro. of hexagon)</h3><h3>3x-20+3x-20+4x+4x+3x-20+3x-20 = 720</h3><h3>3x+3x+3x+3x+4x+4x-20-20-20-20 = 720 (rearranging)</h3><h3>20x - 80 = 720</h3><h3>20x = 720 + 80 </h3><h3>x=800/20</h3>
<h2>x = 40 degrees </h2>
<h3>3x-20 = 100</h3><h3>4x = 160</h3>
<h2>I HOPE THAT THIS ANSWER HELPS YOU</h2>
Answer:
Quadratic equation follows form: ax^2 + bx + c = 0
a = 8
b = - 6
c = 13
Answer:
- sin(2x) = -4/5
- cos(2x) = 3/5
- tan(2x) = -4/3
Step-by-step explanation:
It may be easiest to start with tan(2x).
tan(2x) = 2tan(x)/(1 -tan(x)²)
tan(2x) = 2(-1/2)/(1 -(-1/2)²) = -1/(3/4)
tan(2x) = -4/3 . . . . . still a 4th-quadrant angle
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Then cosine can be found from ...
cos(2x) = 1/√(tan(2x)² +1) = 1/√((-4/3)²+1) = √(9/25)
cos(2x) = 3/5
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Sine can be found from these two:
sin(2x) = cos(2x)tan(2x) = (3/5)(-4/3)
sin(2x) = -4/5
