1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kondaur [170]
4 years ago
8

Why does the internet constantly lie to me when I ask question I need answers for in school?

Computers and Technology
1 answer:
notka56 [123]4 years ago
4 0
Well the website that is trying to tell you the answer is usually the problem. Only websites with .org or .gov are usually reliable because they are run by governments institutes. Websites with the tag .com probably will not be reliable because anyone can make a website today and we don't know if those people are reliable or not.
You might be interested in
Q1. Information systems that monitor the elementary activities and transactions of the organizations are: I a. Management-level
VashaNatasha [74]

Answer:

B. Operational-level systems monitor the elementary activities and transactions of the organization.

6 0
2 years ago
X = 10<br> y = 20<br> x &gt; У<br> print("if statement")<br> print("else statement")
Ksenya-84 [330]

Answer:

n

Explanation:

n

5 0
3 years ago
Write a bool function isPalindrome that takes one string parameter and returns true if that string is a palindrome and false oth
kkurt [141]

Answer:

Here is the bool function isPalindrome:

bool isPalindrome(string s)

{  bool palindrome;      

 int j;

 int len = s.length();

 for (int i =0, j= len-1; i < len/2; i++, j--)  

   if (s[i] == s[j])

     palindrome = true;  

   else

     palindrome = false;

 return palindrome; }

Explanation:

The bool function isPalindrome takes a string as parameter and returns true if the string is a palindrome or false if the string is not palindrome. The string variable s holds the string value. In function isPalindrome, there is a bool type variable palindrome. bool is a data type which is used to hold values true or false which is then stored in the palindrome variable.

Next it is being found that how many characters are there in the input string using length() function which returns the length of the string. The length of the string is stored in int type variable len.

Next the for loop starts which has two variables i and j where i starts at 0 position of the input string and j starts at the last position of the string. These two variables move or traverse along the string this way. i variable stops when half the length of the input string is reached. At the end of every iteration i moves forward by the increment of its value to 1 and j moves backwards by the decrement  of its value to 1.

Every the body of  the loop executes, there is an if condition in the body of the loop which checks if the string is a palindrome. This is checked by matching the character at position/index i with the character at position j of the string. This will continue character by character until the i reached half the length of the input string and if every character in i was matched to every character in j then palindrome = true; statement is executed which returns true as the string is a palindrome otherwise palindrome = false; is returned as the string is not a palindrome.

For taking input string from the user and to check if the function isPalindrome() works correctly a main() function is written which takes input string from the user and reads in variable str calls isPalindrome() function. If the string is palindrome then the cout statement in main() function prints the message: String is a palindrome and if the input string is not a palindrome the the following message is displayed in the output screen: String is not a palindrome

int main()

{

string str;

cout<<"Enter a string: ";

cin>>str;

if(isPalindrome(str))

cout<<"String is a palindrome";

else

cout<<"String is not a palindrome";

}

The screenshot of the program along with the output is attached.

7 0
3 years ago
Mezcla de una señal con otra para facilitar su transporte o transmisión.
Brrunno [24]

Answer:

telecomunicaciones

Explanation:

6 0
3 years ago
Assume a 15 cm diameter wafer has a cost of 12, contains 84 dies, and has0.020 defects /cm2Assume a 20 cm diameter wafer has a c
Vitek1552 [10]

Answer:

1. yield_1=0.959 and yield_2=0.909

2. Cost_1=0.148 and Cost_2=0.165

3. New area per die=1.912 cm^2 and yield_1=0.957

   New area per die=2.85 cm^2  and yield_2=0.905

4. defects=0.042 per cm^2 and defects=0.026 per cm^2

Explanation:

1. Find the yield for both wafers.

yield= 1/(1+(defects per unit area*dies per unit area/2))^2

Wafer 1:

Radius=Diameter/2=15/2=7.5 cm

Total Area=pi*r^2=pi(7.5)^2=176.71 cm^2

Area per die= 176.71/84=2.1 cm^2

yield_1= 1/(1+(0.020*2.1/2))^2

yield_1=1/1.04244=0.959

Wafer 2:

Radius=Diameter/2=20/2=10 cm

Total Area=pi*r^2=pi(10)^2=314.159 cm^2

Area per die= 314.159/100=3.14 cm^2

yield_2= 1/(1+(0.031*3.14/2))^2

yield_2=1/1.0997=0.909

2. Find the cost per die for both wafers.

Cost per die= cost per wafer/Dies per wafer*yield

Wafer 1:

Cost_1=12/84*0.959=0.148

Wafer 2:

Cost_2=15/100*0.909=0.165

3. If the number of dies per wafer is increased by 10% and the defects per area unit increases by 15%, find the die area and yield.

Wafer 1:

There is a 10% increase in the number of dies

10% of 84 =8.4

New number of dies=84.4+8=92.4

There is a 15% increase in the defects per cm^2

15% of 0.020=0.003

New defects per area= 0.020 + 0.003=0.023 defects per cm^2

New area per die= 176.71/92.4=1.912 cm^2

yield_1= 1/(1+(0.023*1.912/2))^2=0.957

Wafer 2:

There is a 10% increase in the number of dies

10% of 100=10

New number of dies=100+10=110

There is a 15% increase in the defects per cm^2

15% of 0.031=0.0046

New defects per area= 0.031 + 0.00465=0.0356 defects per cm^2

New area per die= 314.159/110=2.85 cm^2

yield_2= 1/(1+(0.0356*2.85/2))^2=0.905

4. Assume a fabrication process improves the yield from 0.92 to 0.95. Find the defects per area unit for each version of the technology given a die area of

Assuming a die area of 2cm^2

We have to find the defects per unit area for a yield of 0.92 and 0.95

Rearranging the yield equation,

yield= 1/(1+(defects*die area/2))^2

defects=2*(1/sqrt(yield) - 1)/die area

For 0.92 technology

defects=2*(1/sqrt(0.92) - 1)/2

defects=0.042 per cm^2

For 0.95 technology

defects=2*(1/sqrt(0.95) - 1)/2

defects=0.026 per cm^2

6 0
3 years ago
Other questions:
  • Describe two measures you can use to evaluate whether an attachment in a message is reliable to open.
    8·2 answers
  • Whats the Sioux City school wifi?
    15·2 answers
  • Network administrators ____ to set up the browsers on the network to use a proxy server.
    12·1 answer
  • All of the following are vertical alignment options except __middle , top, center, or_bottom_.
    12·1 answer
  • adding ______around calculations indicates which calculations should be performed first before following the typical order of op
    6·1 answer
  • Help me find the difference between these logos
    10·2 answers
  • Maria is comparing her history project's second-place award to her classmate's first-place award. She starts planning how to win
    9·2 answers
  • Edhesive 3.4 practice 1
    9·1 answer
  • When is mail merge an effective productivity tool<br>​
    5·2 answers
  • HELP!!!!!!!
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!