Answer:
Following are the code to the given question:
#include <iostream>//header file
using namespace std;
int NumberOfPennies(int ND, int NP=0)//defining a method that accepts two parameters
{
return (ND*100 +NP);//use return keyword that fist multiply by 100 then add the value
}
int main() //main method
{
cout << NumberOfPennies(5,6) << endl; // Should print 506
cout << NumberOfPennies(4) << endl; // Should print 400
return 0;
}
Output:
506
400
Explanation:
In the method "NumberOfPennies" it accepts two parameters that are "ND and NP" that uses the return keyword that multiply 100 in ND variable and add in NP variable and return its values.
In the main method it it uses the cout method that call the by accepts value in parameter and print its value.
Answer:
On your desktop, hover over the message you'd like to share and click the Share message icon on the right. Use the drop-down menu to choose where you'd like to share the message, and add a note if you'd like. Click Share to see the message expand.
Explanation:
Operating System (OS) is the answer.
An application runs in/on an OS. It is not the OS itself. Like Word or Chrome are applications.
Systems is too generic and not specific enough to mean anything in this context. Throw away answer.
Network Operating System does not 'usually' run on a hard drive but on memory chips in things like routers, wireless access points and switches that move network traffic.
Answer:
public class Brainly
{
public static void main(String[] args)
{
BinaryConverter conv = new BinaryConverter();
String binStr = "01001101";
System.out.print(binStr + " in decimal is "+conv.BinToDec(binStr));
}
}
public class BinaryConverter
{
public int BinToDec(String binStr)
{
int d = 0;
while(binStr.length() > 0)
{
d = (d << 1) + ((binStr.charAt(0) == '1') ? 1: 0);
binStr = binStr.substring(1);
}
return d;
}
}
Explanation:
The program "eats" the string from left to right, and builds up the integer representation in variable "d" on the go. While there are digits left, it shifts the previous result to the left and sets the least signficant bit to 1 only if the corresponding string character is a 1.
